All categories

3 years ago

Find the slope of the line connecting the point (8,12) to the point (16,16)

Mathematics

1 answer:

dangina [55]3 years ago

6 0

Answer:

The slope is <u>2</u>

Step-by-step explanation:

For this we use this slope formula

$\frac{y_{2}-y_{1} }{x_{2} -x_{1} }$

These are our pairs

(8, 12) (16, 16)

x1 y1 x2 y2

$\frac{16-8}{16-12} = \frac{8}{4}$

8/4=2

<u> M=2</u>

You might be interested in

List the sides of each triangle in order form shortest to longest.

Ivan

Answer:

1. segments Q,R

2. segments R,S

3. segments Q,S

Step-by-step explanation:

8 0

3 years ago

A group of scientists studied the effect of a chemical on various strains of bacteria. Strain A started with 6000 cells and decr

forsale [732]

After 3 hours each strain will have been depleted completely to 0 cells. Given the numbers 6000 and 2000, you will find that a decrease of 33.33333% for strain A and a 50% decrease for strain B will not intercept on the same hour. Strain B will have been depleted for an hour at the time that strain A is gone.

5 0

4 years ago

(Differential Equations) Put these equations in explicit form:

Nuetrik [128]

Answer:

1. $y= C(t*exp(-\frac{t^{2} }{2(2!)}+\frac{t^{4} }{4(4!)}-\frac{t^{6} }{6(6!)}+... ))}$

2. $t+C=ln(csc(y)-cot(y)$ $23. [tex]Assuming t as independent variable:F(r,t)=t+\frac{1}{m} exp(m+r)+\frac{r^{2} }{2} =C\\Step-by-step explanation:1. Separable variables:[tex]\frac{dy}{dt}=\frac{y*cos(t) }{t}\\ \frac{dy}{y}= \frac{cos(t) }{t}dt\\ \int {\frac{dy }{y}} \, dt=\int {\frac{cos(t) }{t}} \, dt \\ln(y)-ln(C)=ln(t)-\frac{t^{2} }{2(2!)} +\frac{t^{4} }{4(4!)} -\frac{t^{6} }{6(6!)}+... \\y=C(t*exp(\frac{t^{2} }{2(2!)} +\frac{t^{4} }{4(4!)} -\frac{t^{6} }{6(6!)}+...))$

2. Separable variables

\frac{dy}{sin(y)}=dt\\ \int\ \frac{1}{sin(y)}} \, dy = \int\ 1} \, dt\\t+C=ln(csc(y)-cot(y))[/tex]

3. Homogeneous D.E

Rewriting:

$dr+(\frac{1}{m} exp(m+r)+r)dt=0\\\frac{dF}{dt}=1 -> F(r,t)=t+C(r)\\\frac{dF}{dy}=0+C'(r)= \frac{1}{m} exp(m+r)+r -> C(r)=\frac{1}{m} exp(m+r)+\frac{r^{2} }{2} \\F(r,t)=t+\frac{1}{m} exp(m+r)+\frac{r^{2} }{2} =C\\$

7 0

3 years ago

A car start from rest and accelerates at the rate of 2m/s² for 5 seconds. it maintenance this velocity for another 5 seconds. it

Vladimir79 [104]

Answer:

2m/s² ; - 2m/s²

25m ; 50m ; 25m

6.67 m/s²

Step-by-step explanation:

The acceleration and deceleration :

Both rates are the Same from the graph ;

According to scenario described, acceleration = 2m/s²

Deceleration occurred in equal time interval = - 2m/s

Distance covered during each stage:

Stage 1 : area of triangle

0.5 * base * height

0.5 * 5 * 10 =25 m

Stage 2: area of rectangle :

Length * breadth = 5 * 10 = 50 m

Stage 3 : area of triangle

0.5 * base * height

0.5 * 5 * 10 =25 m

Average Velocity :

Total distance / time = (25 + 50 + 25) / 15 = 100/ 15 = 6. 67 m/s

5 0

3 years ago

Mr. Marvi's Class is fund-raising for a field trip that costs $1254. The school is

RUDIKE [14]

Answer:

idek but I'll try solving it I'm hyu when I'm done

5 0

4 years ago

Read 2 more answers