<span>Let be the length, and be the width.
If the length is 1.6 times the width, then
If the sum of the length and with (in feet) is 130, then
</span><span>Substituting in the equation above, the expression for , we get
--> --> -->
Ten, substituting the value found for in we find
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The two equations we set up at the start form a system of linear equations:
</span>
Answer: the length and width are
(x + 8) and (x + 8)
Step-by-step explanation:
The rug has an area represented by the expression
Area = 4x² + 64x + 256.
The factors in the factored expressions represent the length and width of the rug.
Dividing the the equation by 4, it becomes
x² + 16x + 64 = 0
We would find two numbers such that their sum or difference is 16x and their product is 64x^2.
The two numbers are 8x and 8x. Therefore,
x² + 8x + 8x + 64 = 0
x(x + 8) + 8(x + 8) = 0
The factors are
(x + 8)(x + 8)
Answer:
Step-by-step explanation:
omg are you in school do you have to go on the board bc you dead meat
On month -------- 10%
12 month ---------- x %
-------------------------------
x = 12*10/1 = 12*10 = 120%
Answer:
80 feet
Step-by-step explanation:
Given:
Initial speed of the car (
) = 40 ft/sec
Deceleration of the car (
) = -10 ft/sec²
Final speed of the car (
) = 0 ft/sec
Let the distance traveled by the car be 'x' at any time 't'. Let 'v' be the velocity at any time 't'.
Now, deceleration means rate of decrease of velocity.
So, 
Negative sign means the velocity is decreasing with time.
Now, 
using chain rule of differentiation. Therefore,
Integrating both sides under the limit 40 to 0 for 'v' and 0 to 'x' for 'x'. This gives,
![\int\limits^0_{40} {v} \, dv=\int\limits^x_0 {-10} \, dx\\\\\left [ \frac{v^2}{2} \right ]_{40}^{0}=-10x\\\\-10x=\frac{0}{2}-\frac{1600}{2}\\\\10x=800\\\\x=\frac{800}{10}=80\ ft](https://tex.z-dn.net/?f=%5Cint%5Climits%5E0_%7B40%7D%20%7Bv%7D%20%5C%2C%20dv%3D%5Cint%5Climits%5Ex_0%20%7B-10%7D%20%5C%2C%20dx%5C%5C%5C%5C%5Cleft%20%5B%20%5Cfrac%7Bv%5E2%7D%7B2%7D%20%5Cright%20%5D_%7B40%7D%5E%7B0%7D%3D-10x%5C%5C%5C%5C-10x%3D%5Cfrac%7B0%7D%7B2%7D-%5Cfrac%7B1600%7D%7B2%7D%5C%5C%5C%5C10x%3D800%5C%5C%5C%5Cx%3D%5Cfrac%7B800%7D%7B10%7D%3D80%5C%20ft)
Therefore, the car travels a distance of 80 feet before stopping.
