Graph the circle which is centered at (3,-2) and has a radius of 5 units.
1 answer:
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9.
By the Segment Addition Postulate, SAP, we have
XY + YZ = XZ
so
YZ = XZ - XY = 5 cm - 2 cm = 3 cm
10.
M is the midpoint of XZ=5 cm so
XM = 5 cm / 2 = 2.5 cm
11.
XY + YM = XM
YM = XM - XY = 2.5 cm - 2 cm = 0.5 cm
12.
The midpoint is just the average of the coordinate A(-3,2), B(5,-4)
Answer: M is (1,-1)
You'll have to plot it yourself.
13.
For distances we calculate hypotenuses of a right triangle using the distnace formula or the Pythagorean Theorem.
Answer: AB=10
M is the midpoint of AB so
Answer: AM=MB=5
14.
B is the midpoint of AC. We have A(-3,2), B(5,-4)
B = (A+C)/2
2B = A + C
C = 2B - A
C = ( 2(5) - -3, 2(-4) - 2 ) = (13, -10)
Check the midpoint of AC:
(A+C)/2 = ( (-3 + 13)/2, (2 + -10)/2 ) = (5, -4) = B, good
Answer: C is (13, -10)
Again I'll leave the plotting to you.
Answer:
solution: x= 0.273, y= 1.909.
Step-by-step explanation:
- given system of linear equations : x+3y=64x−6y=6
- these can also be splitted or written individually as:
x+3y=6 & 64x−6y=6
- the first equation can also be written as,
so, it is line with slope : -1/3 and y-intercept :2
- the second equation can also be written as,
so, it is line with slope : 32/3 and y-intercept : -1
- now we can easily draw graphs for these equations using the above interpretation.
- graph is in the attachment.
- so, the solution is: x= 0.273, y= 1.909.
