Answer:
Step-by-step explanation:
ABCD is a parallelogram. AB is produced to P, such that AB = BP and PQ is drawn parallel to BC to meet AC produced at Q. Given AB = 8 cm, AD = 5 cm, AC = 10 cm.
→ BC ║ QP →→Given
In Δ ABC and ΔAPQ
∠ABC=∠APQ→→[BC ║ QP , BP is a transversal, so corresponding angles are equal]
∠BAC=∠PAQ→→Reflex angle
Δ ABC ~ ΔAPQ→→(AA similarity criterion]
When triangles are similar, their corresponding angles are equal.
AC=CQ=10 cm, shows that point C is mid point of AQ.
<u>help me by marking as brainliest....</u>
From the given graph, the image is a trapezoid.
Therefore,
The first option,
"t<span>
he polygon is a rectangle" is incorrect.
The second option "</span><span>Adjacent sides of the polygon are perpendicular." cannot be true as well because trapezoid has one the adjacent sides which is not perpendicular.
Third option" </span><span>Opposite sides of the polygon are parallel", this can't be true as well because only two sides are parallel.
Fourth option " </span><span>The slope of side c is 0.", this is true because line c is a horizontal line with zero rise and maximum run. Therefore,
Slope = 0 </span>÷ 9
<span> = 0
</span>
Answer:
sin( -∅ )
- 1 / csc ( ∅ )
1 / csc ( -∅ )
Step-by-step explanation:
Since sin(x) is and odd function (a function where f(-a) = f(a) ).
-sin( ∅ ) = sin( -∅ )
On the other hand, we know that sin( ∅ ) = 1 / csc ( ∅ )
Another odd function, so the same as before applies.
-sin( ∅ ) = -1 / csc ( ∅ )
-sin( ∅ ) = 1 / csc ( -∅ )