1 answer:
We have,
(2y)^3 × y^-1
Simplify the term (2y)^3
= 8y^3 × y^-1
Now, multiply the terms with the same base y by adding their exponents.
Note: Using exponent product rule x^y × x^z = x^(y+z)
= 8y^{3+(-1)}
= 8y^(3-1)
= 8y^(3-1)
= 8y^2
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