Hello, so the equation for the area of a trapezoid is A = (a+b)*(h/2)
In which, a is one of the bases, b is the other base, and h is the height. A is the Area. If you wanna solve for height, rearrange the equation to what h equals.
First divide (a+b) from both sides
<span>A/(a+b) = h/2 </span>
Now multiply 2 on both sides
2(A/(a+b)) = h
Now you have it rearranged equal to just h. Plug in the values now.
2(3.9/(4+2.5)) = h
2(3.9/(6.5)) = h
2(.6) = h
1.2 = h
<span>The section is 1.2 centimeters tall.your welcome</span>
(3x^2 - 2x)(x + 4)
<em><u>First step would be: distributive property.</u></em>
3x^3 + 12x^2 - 2x^2 - 8x
<em><u>Combine like terms.</u></em>
3x^3 + 10x^2 - 8x is the simplified form of the functions multiplied.
Your answer is D.
Archimedes principle comes to play in this scenario: The weight of water displaced equals the weight of the steel block.
Weight = density*volume
In other words,
Density of steel block*it volume = Density of water displaced*its volume
Therefore,
Volume of water displaced = (density of block*its volume)/Density of water = (2.5*10^3*8*10^3)/(1*10^3) = 20000 m^3 = 2*10^4 m^3
This displacement of water can be achieved by lifting the tank mechanically.
Answer:
R=5.5%, P=$1000, T=5yrs
I=PRT/100
I=5.5×1000×5/100
I=$275.00 for the account one, the account two will be $250.00 by comparing, the account one is close to the interest
