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Vedmedyk [2.9K]
3 years ago
11

Is y= -9/5x + 1/5 perpendicular to y= 5/9x + 2/9

Mathematics
1 answer:
Lana71 [14]3 years ago
7 0

The given lines are perpendicular to each other.

Further explanation:

Given lines are:

Line 1: y= -9/5x + 1/5

Line 2:  y= 5/9x + 2/9

As the lines are in slope=intercept form, the co-efficient of x are their slopes

Let m1 be the slope of line 1 and m2 be the slope of line 2

Then

m_1=-\frac{9}{5}\\m_2=\frac{5}{9}\\m_1.m_2=-\frac{9}{5}*\frac{5}{9}\\m_1.m_2=-1

As we can see that the product of slopes of both lines is -1. The product of slopes of perpendicular lines is -1.

The given lines are perpendicular to each other.

Keywords: Slope, slope-intercept form

Learn more about equation of lines at:

  • brainly.com/question/4703807
  • brainly.com/question/4710621

#LearnwithBrainly

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A population increases 3% each year. If the city is now 5 million, what will the population be in 5 years?
Step2247 [10]
5 million x 3% = 150,000
1 Year = 5,150,000

5.15 million x 3% = 154,500
2 Years = 5,304,500

5,304,500 x 3% = 159,135
3 Years = 5,463,635

5,463,635 x 3% = 163,909.05
4 Years = 5,627,544.05

5,627,544.05 x 3% = 168,826.322
5 Years = 5,796,370.37

After 5 years, the population will be 5,796,370.37
8 0
4 years ago
What is the arc length of an arc with radius 15 inches and central angle 30 degrees
RUDIKE [14]

Answer:

7.855 inches

Step-by-step explanation:

The formula to find the length of an arc is :

Arc Length = \frac{\theta}{360} × 2 π r

Here,

Θ ⇒ size of the angle ⇒ 30°

r ⇒ radius ⇒ 15 inches

<u>Let us solve it now.</u>

Arc length = \frac{\theta}{360} × 2 π r

Arc length = \frac{30}{360}*2*\pi*15

Arc length = \frac{30*2*\pi*15}{360}

Arc length = \frac{2827.8}{360}

Arc length = 7.855 inches

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7 0
2 years ago
Evan said that the difference between two negative numbers must be negative. Was he right? Use examples to illustrate your answe
vladimir1956 [14]
Yes he is right because if u have


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8 0
3 years ago
Find the solution r(t)r(t) of the differential equation with the given initial condition: r′(t)=⟨sin4t,sin7t,9t⟩,r(0)=⟨9,8,3⟩
Makovka662 [10]
\mathbf r'(t)=\langle\sin4t,\sin7t,9t\rangle
\implies\mathbf r(t)=\displaystyle\int\mathbf r'(t)\,\mathrm dt
\mathbf r(t)=\displaystyle\left\langle\int\sin4t\,\mathrm dt,\int\sin7t\,\mathrm dt,\int9t\,\mathrm dt\right\rangle
\mathbf r(t)=\left\langle-\dfrac14\cos4t+C_1,-\dfrac17\cos7t+C_2,-\dfrac92t^2+C_3\right\rangle

With \mathbf r(0)=\langle9,8,3\rangle, we have

\langle9,8,3\rangle=\left\langle-\dfrac14+C_1,-\dfrac17+C_2,C_3\right\rangle
\implies C_1=\dfrac{37}4,C_2=\dfrac{57}7,C_3=8
\implies\mathbf r(t)=\left\langle-\dfrac14\cos4t+\dfrac{37}4,-\dfrac17\cos7t+\dfrac{57}7,-\dfrac92t^2+8\right\rangle
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sergeinik [125]

Answer:

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Step-by-step explanation:

Brainliest PLS

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3 years ago
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