(2x + 3y = 12) x (-2)
(4x - 3y = 6) x 1
-4x - 6y = -24
4x - 3y = 6
You can cancel out the x values by adding the two equations together.
(-4x + 4x) + (-6y - 3y) = (-24 + 6)
-9y = -18
y = 2
Solve for x now...
4x - 3(2) = 6
4x - 6 = 6
4x = 12
x = 3
Check... (x = 3, y = 2)
2(3) + 3(2) = 12
6 + 6 = 12
12 = 12 <- this works!
4(3) - 3(2) = 6
12 - 6 = 6
6 = 6 <- this works!
4m + 7 = -3m + 49
4m + 3m = 49 - 7
7m = 42
m = 42/7
m = 6
So, your final answer is 6
Hope this helps!
Answer:
24a
Step-by-step explanation:
See the attached figure
DB = 4 and DC = 6 , We need to find AD
Using <span>Euclid's theorem for the right triangle
</span><span>
</span><span>∴ DB² = AD * DC
</span><span>
</span><span>∴ 4² = AD * 6
</span><span>
</span><span>∴ 6 AD = 16
</span><span>
</span><span>
</span><span>
∴ AD = 16/6 = 8/3 ≈ 2.67</span>