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2 years ago

What is the right answer

Mathematics

2 answers:

Lostsunrise [7]2 years ago

4 0

Answer:

B) y = 1/3x - 2

Step-by-step explanation:

i plotted the points on a graph and found the rise and the run

OverLord2011 [107]2 years ago

4 0

B .......is the answer

You might be interested in

Which expression is equivalent to(2^3)^-5

Nady [450]

Answer:

hope this helps if not im sorry

Step-by-step explanation:

(2^3)^5

=2^(3*5)

= 2^15

3 0

2 years ago

Let f(x) = 1/x^2 (a) Use the definition of the derivatve to find f'(x). (b) Find the equation of the tangent line at x=2

Verdich [7]

Answer:

(a) $f'(x)=-\frac{2}{x^3}$

(b) $y=-0.25x+0.75$

Step-by-step explanation:

The given function is

$f(x)=\frac{1}{x^2}$ .... (1)

According to the first principle of the derivative,

$f'(x)=lim_{h\rightarrow 0}\frac{f(x+h)-f(x)}{h}$

$f'(x)=lim_{h\rightarrow 0}\frac{\frac{1}{(x+h)^2}-\frac{1}{x^2}}{h}$

$f'(x)=lim_{h\rightarrow 0}\frac{\frac{x^2-(x+h)^2}{x^2(x+h)^2}}{h}$

$f'(x)=lim_{h\rightarrow 0}\frac{x^2-x^2-2xh-h^2}{hx^2(x+h)^2}$

$f'(x)=lim_{h\rightarrow 0}\frac{-2xh-h^2}{hx^2(x+h)^2}$

$f'(x)=lim_{h\rightarrow 0}\frac{-h(2x+h)}{hx^2(x+h)^2}$

Cancel out common factors.

$f'(x)=lim_{h\rightarrow 0}\frac{-(2x+h)}{x^2(x+h)^2}$

By applying limit, we get

$f'(x)=\frac{-(2x+0)}{x^2(x+0)^2}$

$f'(x)=\frac{-2x)}{x^4}$

$f'(x)=\frac{-2)}{x^3}$ .... (2)

Therefore $f'(x)=-\frac{2}{x^3}$ .

(b)

Put x=2, to find the y-coordinate of point of tangency.

$f(x)=\frac{1}{2^2}=\frac{1}{4}=0.25$

The coordinates of point of tangency are (2,0.25).

The slope of tangent at x=2 is

$m=(\frac{dy}{dx})_{x=2}=f'(x)_{x=2}$

Substitute x=2 in equation 2.

$f'(2)=\frac{-2}{(2)^3}=\frac{-2}{8}=\frac{-1}{4}=-0.25$

The slope of the tangent line at x=2 is -0.25.

The slope of tangent is -0.25 and the tangent passes through the point (2,0.25).

Using point slope form the equation of tangent is

$y-y_1=m(x-x_1)$

$y-0.25=-0.25(x-2)$

$y-0.25=-0.25x+0.5$

$y=-0.25x+0.5+0.25$

$y=-0.25x+0.75$

Therefore the equation of the tangent line at x=2 is y=-0.25x+0.75.

5 0

3 years ago

10x+20=7x-8<br><br> Solve for x.

Kazeer [188]

Step-by-step explanation:

Isolate the variable

10x - 7x = -20 - 8

3x = -28

x = -9.333333333333

5 0

2 years ago

The temperature at 6.00 am was - 12 the temperature increased by 1/2 each hour for 6 hours what was the temperature in degrees F

Illusion [34]

Answer: -9 degrees Fahrenheit

Step-by-step explanation:

Given: Temperature at 6:00 AM = -12 degrees Fahrenheit

Temperature increased each hour = $\dfrac12$ degrees Fahrenheit

Temperature increase in 6 hours = $6\times\dfrac12=3\text{ degrees Fahrenheit}$

Temperature at noon = Temperature at 6:00 AM+Temperature increase in 6 hours

= -12+3 degrees Fahrenheit

= -9 degrees Fahrenheit

Hence, the temperature in degrees Fahrenheit at noon= -9 degrees Fahrenheit

8 0

2 years ago

3/8 x 5 as a mixed number

leva [86]

Answer:

1 7/8

Step-by-step explanation:

3/8 * 5/1 = 15/8

<-- First multiply 3/8 by 5

----------------------------------------------

15/8 = 1 with a remainder of 7

<-- Then convert 15/8 to a mixed number by dividing 15 by 8

15/8 = 1 7/8

8 0

1 year ago