Answer:
A Hercules Beetle is 6.97 inches larger than A ladybug
Step-by-step explanation:
A hercules beetle is 7 inches long while a ladybug is about 0.03 cm long when subtracting these two you will get a grand total of 6.97.
Answer:
9/12
Step-by-step explanation:
3/4 times 3 = 9/12
3/4 is equivalent to 9/12 so those would be the two anwsers
Answer: L = 29cm
Step-by-step explanation:
Let's go!!
To find any rectangle area, you have to apply this formula: A = L . w , where L is the length and w is the width.
So, we have w = L - 13 (the width is 13 less than the Length) and then, perimeter is 90 cm.
Well, I hope you remember that the perimeter of rectangle is 2L + 2W. In this case, 2L + 2w = 90
Then, you might to solve this system of equation:
2L + 2w = 90
w = L - 13
Simplifying the first equation, you'll have L + w = 45 (you can divide everything of 2).
Our new system:
L + w = 45
w = L - 13
Using the substituition method:
L + L - 13 = 45
2L = 58
L = 29 cm
the width is 29 - 13 = 16 cm
Your answer is c i pretty insurance
