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Kitty [74]
3 years ago
13

Academic integrity only relates to a. Online learning c. Instances of cheating b. All subjects d. Any academic situation I give

brainliness
Physics
1 answer:
alukav5142 [94]3 years ago
3 0

Answer:

answer is d.

Explanation:

are you going to mark me  brainlinessist

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The speed of a 500 g cricket ball changes from 10m/s to 30m/s in just 7 seconds. What is the force acting on the cart?
9966 [12]

The force acting on the cart is 1.43 N.

<h3>What is force?</h3>

Force can be defined as the product of mass and acceleration.

To calculate the force acting on the cart, we use the formula below.

Formula:

  • F = m(v-u)/t................. Equation 1

Where:

  • F = Force acting on the cart
  • m = mass of the cart
  • v = Final velocity
  • u = initial velocity
  • t = time

From the question,

Given:

  • m = 500 g = 0.5 kg
  • v = 30 m/s
  • u = 10 m/s
  • t = 7 seconds

Substitute these values into equation 1

  • F = 0.5(30-10)/7
  • F = 10/7
  • F = 1.43 N.

Hence, the force acting on the cart is 1.43 N.

Learn more about force here: brainly.com/question/13370981

7 0
3 years ago
Which is not a way to accelerate an object?
GREYUIT [131]
<span>Slowing an object down is not a means of accelerating it. It actually decelerates the motion of an object. Speeding it up, changing its direction and applying balanced forces accelerate an object. In order for an object to accelerate, a force must be applied. It follows Newton’s second law of motion where it states that a body at rest remains at rest unless a force is acted upon it. When you move an object, you are exerting a force onto it. By exerting a force on the object, you are actually displacing it from its initial position. You cannot apply force to the object without altering its position. Keep in mind that when you exert work, you are exerting energy too. </span>
6 0
3 years ago
A mover loads a 100 kg box into the back of a moving truck by
hammer [34]

Explanation:

Mechanical Advantage (MA)

MA=d1d2=FoutFin ; d1 is the distance of effort, d2 is the distance the object is moved

7 0
3 years ago
The following are all potential explanations for the motion of sailing rocks, but not all of them are scientific hypotheses give
AleksAgata [21]

Answer:

As we know that science is based upon logic. So the scientific theories have a logical reasoning behind them. So considering that in mind, scientific hypothesis include the motion of sailing rocks by animals, wind, flowing water, magnetic field, humans and gravity. The motion of the rocks by ghosts, God and magic are not scientific theories as we can not prove them logicaly.

Explanation:

6 0
4 years ago
A farm truck travels due east with a constant speed of 9.50 m/s along a horizontal road. A boy riding in the back of the truck t
Reil [10]

Answer:

a)he angle is 90 with respect to the horizontal (x axis)

b) its speed is zero both vertically and horizontally

c)  vertical path

d)  a parabolic movement

e)  v₀ = (9.5i ^ + 8.232 j ^) m / s

Explanation:

This is a relative problem and movement.

            .v ’= v + u

Where v ’is the speed with respect to the mobile system, v the speed with respect to the fixed system and the speed between the two reference systems

a) The child and the can is in the truck, so they go at the speed of the truck, when he throws the can he continues at this speed on the x-axis and therefore as the two advance the same distance the more hands of the child, consequently the can is thrown vertically

The angle is 90 with respect to the horizontal (x axis)

b) with respect to the truck, the can is still, so its speed is zero both vertically and horizontally

c) The child sees that the can follows a vertical path

d) A stationary observer on the ground, sees that the can has a constant speed in the same direction of the truck and when they throw it vertical goal has a vertical movement, the sum of these two movements gives a parabolic movement of the same uncle as a projectile launch

e) the initial speed has two components

X Axis         v_lata = v_camion = 9.5 m / s

Y Axis          speed given by the child

Let's look for the travel time

         x = v₀ₓ t

         t = x / v₀ₓ

         t = 16 / 9.5

         t = 1.68 s

     

         y = v_{oy} t - ½ g t²

When he returns to the child's hand and = 0

          0 = v_{oy} t - ½ g t²

          v_{oy} = ½ g t

          v_{oy} = ½  9.8  1.68

          v_{oy} = 8,232 m / s

Speed ​​is

         v₀ = (9.5i ^ + 8.232 j ^) m / s

5 0
4 years ago
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