A 5.0-Ω resistor and a 9.0-Ω resistor are connected in parallel. A 4.0-Ω resistor is then connected in series with this parallel
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Answer:
<em>P = 66.67 W</em>
Explanation:
<u>Joule Heating</u>
It's the process by which the electric current passing through a conductor produces heat.
Also known as Joule's first law or the Joule–Lenz law, states that the power of heating generated by an electrical conductor (P) is proportional to the product of its resistance (R) and the square of the current (I).
It can be described by the equation that follows:
Also, we can calculate the voltage V with the formula of Ohm's law:
Combining both equations, power can be related to the voltage:
Given the power and the voltage, the resistance can be calculated by solving for R:
There are two bulbs marked P=200W V=250V and P=100 W V=250.
The first bulb has a resistance of:
The first bulb has a resistance of:
When connected in series, the total resistance is
The total power consumed when connecting them to a V=250 V supply is:
P = 66.67 W
Hi there!
We must begin by converting km/h to m/s using dimensional analysis:
Now, we can use the kinematic equation below to find the required acceleration:
vf² = vi² + 2ad
We can assume the object starts from rest, so:
vf² = 2ad
(17.22)²/(2 · 75) = a
a = 1.978 m/s²
Now, we can begin looking at forces.
For an object moving down a ramp experiencing friction and an applied force, we have the forces:
Fκ = μMgcosθ = Force due to kinetic friction
Mgsinθ = Force due to gravity
A = Applied Force
We can write out the summation. Let down the incline be positive.
ΣF = A + Mgsinθ - μMgcosθ
Or:
ma = A + Mgsinθ - μMgcosθ
We can plug in the given values:
22(1.978) = A + 22(9.8sin(5)) - 0.10(22 · 9.8cos(5))
A = 46.203 N
Answer:
Explanation:
given,
moles of air compressed, n = 1.70 mol
initial temperature, T₁ = 390 K
Power supply by the compressor, P = 7.5 kW
Heat removed = 1.3 kW
Angular frequency of the compressor, f = 110 rpm = 110/60 = 1.833 rps.
Time of compression = time of the hay revolution
=
=
=
=0.273 s
Using first law of thermodynamics
U = Q - W
now,
Power supplied = 7.5 kW
heat removed = 1.3 kW
now,
we know,
C_v for air = 5 cal/° mol
= 5 x 4.186 J/mol°C = 20.93 J/mol°C
now,
the temperature change per compression stroke is equal to 47.57°C.