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Afina-wow [57]
3 years ago
10

The largest watermelon ever grown had a mass of 118 kg. Suppose this watermelon were exhibited on a platform 5.00 m above the gr

ound. After the exhibition, the watermelon is allowed to slide along to the ground along a smooth ramp. How high above the ground is the watermelon at the moment its kinetic energy is 4.61 kJ?
Physics
1 answer:
WINSTONCH [101]3 years ago
6 0

Answer: height = 3.98m

Explanation: by placing the watermelon at a height above the ground, it has a potential energy of the formulae

p = mgh

p = potential energy = 4.61kJ = 4610J

m = mass of watermelon = 118 kg

g = acceleration due gravity = 9.8 m/s²

4610 = 118 * 9.8 * h

h = 4610/ 118 * 9.8

h = 4610/ 1156.4

h = 3.98m

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Natalka [10]

Answer:

length of one side of the coil is 0.1083 m

Explanation:

given data

no of turn = 269

coil rotates = 113 rad/s

magnetic field = 0.222-T

peak output = 79.2 V

solution

we will apply here formula for maximum emf induced in a coil that is

εo = N × A × B × ω    ........................1

and here Area A = l²

so

l = \sqrt{A}

put here value of A from equation 1

I = \sqrt{\frac{\epsilon _o}{N\times B\times \omega} }  

put here value and we will get

l =  \sqrt{\frac{79.2}{269\times 0.222\times 113}}

l = 0.1083 m

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4 years ago
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3 years ago
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Make me laugh and I’ll mark brainliest
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OKAy okay here Please laugh kinda cringe but...

Explanation:

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The temperature of a substance depends on what two types of energy​
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Answer:

Thermal and kinetic.

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3 years ago
A 750-kg car moving at 23 m/s brakes to a stop. Assume that all the kinetic energy is transformed into thermal energy. The brake
ahrayia [7]

Answer:

The temperature of the brakes is 29.38°C.

Explanation:

Given that,

Mass of car = 750 kg

Speed = 23 m/s

Mass of iron = 15 kg

We need to calculate the kinetic energy of car

Using formula of kinetic energy

K.E=\dfrac{1}{2}mv^2

K.E=\dfrac{1}{2}\times750\times23^2

K.E=198.375\ kJ

We need to calculate the temperature of the brakes

Using formula of energy

K.E=mc\Delta T

Put the value into the formula

198.375=15\times0.450\times\Delta T

\Delta T=\dfrac{198.375}{15\times0.450}

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