Answer: With that assumption, we have a square, whose area is given by the formula Asquare=a2, and two semicircles. The distance D is simply the square's diagonal. The area of each semicircle is given by the formula Asemicircle=π*r2/2. then you will get your answer!
Answer:
{x,y} = {6/5,23/10}
Step-by-step explanation:
[1] 7x + 2y = 13
[2] 4x + 4y = 14 <---------- linear equations given
Graphic Representation of the Equations : PICTURE
2y + 7x = 13 4y + 4x = 14
Solve by Substitution :
// Solve equation [2] for the variable y
[2] 4y = -4x + 14
[2] y = -x + 7/2
// Plug this in for variable y in equation [1]
[1] 7x + 2•(-x +7/2) = 13
[1] 5x = 6
// Solve equation [1] for the variable x
[1] 5x = 6
[1] x = 6/5
// By now we know this much :
x = 6/5
y = -x+7/2
// Use the x value to solve for y
y = -(6/5)+7/2 = 23/10
// Plug this in for variable y in equation [1]
[1] 7x + 2•(-x +7/2) = 13
[1] 5x = 6
// Solve equation [1] for the variable x
[1] 5x = 6
[1] x = 6/5
// By now we know this much :
x = 6/5
y = -x+7/2
// Use the x value to solve for y
y = -(6/5)+7/2 = 23/10
Answer:
2/7.
Step--step explanation:
1/2 * 4/7.
Multiply the numerators and the denominators:
= 1*4 / 2*7
= 4 / 14 Now divide numerator and denominator by 2:
= 2/7.
Answer:
16
Step-by-step explanation:
Dealing with a fraction exponent on hand can be converted by using the fractional exponents rule where the fraction exponent is converted to something like this:
![64^\frac{2}{3} = \sqrt[3]{64^{2}}\\](https://tex.z-dn.net/?f=64%5E%5Cfrac%7B2%7D%7B3%7D%20%3D%20%5Csqrt%5B3%5D%7B64%5E%7B2%7D%7D%5C%5C)
As you can see, the denominator of the fractional exponent is now the index of the radical. Here is a guide to know what goes where.
![64^\frac{x}{y} = \sqrt[y]{64^{x}}](https://tex.z-dn.net/?f=64%5E%5Cfrac%7Bx%7D%7By%7D%20%3D%20%5Csqrt%5By%5D%7B64%5E%7Bx%7D%7D)
Both the original problem (64^2/3) and the converted formula can be put into a calculator.
<u>Simplify (if you want to)</u>
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64 to the power of 2/3 is 16.