Answer:
the answer is 134 hope this helps.
Y=33x + 104 -(45+66).......
Answer:
1:
p-r/6=-6-(-6)/6=-6+1=<u>-</u><u>5</u>
<u>2</u><u>:</u>
<u>p-</u><u>(</u><u>m-n</u><u>)</u><u>=</u> -1-(-4-4)=-1-(-8)=-1+8=<u>7</u>
3:
(z+y)/2)3=(-5-4)/3=-9/3=<u>-</u><u>3</u>
<u>4</u><u>:</u>
m/6-n=6/6-6=1-6=<u>-</u><u>5</u>
5:
k³-h=3³-(-2)=27+2=<u>2</u><u>9</u>
6:
p-(p-(m-3))=5-(5-(4-3))=5-(5-1)=5-4=<u>1</u>
7:
(k)(k-j)+3=(5)(5-5)+3=5*0+3=<u>3</u>
8.
p²/6-q=6²/6-4=6-4=<u>2</u>
<u>9</u><u>;</u>
zx+3³=6*4+3³=24+27=<u>5</u><u>1</u><u>.</u>
<u>1</u><u>0</u><u>:</u>
<u>y</u><u>+</u><u>z</u><u>-</u><u>(</u><u>y</u><u>-</u><u>x</u><u>)</u><u>=</u>5+4-(5-2)=9-3=<u>6</u>
<u>S</u><u>o</u><u>m</u><u>e</u><u> </u><u>b</u><u>a</u><u>s</u><u>i</u><u>c</u><u> </u><u>r</u><u>u</u><u>l</u><u>e</u><u>s</u><u>:</u>
+. +. +=+
+. * +=+
+. ÷ +=+
+. - +=+
and
+. +. -=add and put sigh of greater one.
-. * +=-sigh
-÷-=+sigh
- - -=add and put - sigh
We know that the perimeter of a rectangle is 2(width)+2(length). We can multiply the length by 2 to find out how much remaining fencing we have, then divide that number by 2 to find the width.
15.5*2=31
170.5-31=139.5
139.5/2=69.75
A possible width is 69.75 feet.
Log w (x^2-6)^4
Using log a b = log a + log b, with a=w and b=(x^-6)^4:
log w (x^2-6)^4 = log w + log (x^2-6)^4
Using in the second term log a^b = b log a, with a=x^2-6 and b=4
log w (x^2-6)^4 = log w + log (x^2-6)^4 = log w + 4 log (x^2-6)
Then, the answer is:
log w (x^2-6)^4 = log w + 4 log (x^2-6)
