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Montano1993 [528]
3 years ago
10

Given g(x)=x^2-7x+1/4 show that the least possible value of g(x) is -12

History
1 answer:
nadezda [96]3 years ago
7 0
   
\displaystyle\\
g(x)=x^2-7x+\frac{1}{4} \\  \\ 
g(x)=x^2-7x+0.25\\  \\ \\  \\ 
x \text{ for  } g_{min} = \frac{-b}{2a}=\frac{-(-7)}{2\times 1}= \frac{7}{2}=3.5 \\  \\ 
g_{min} = g(3.5) = (3.5)^2 -7\times 3.5 + 0.25= 12.25 - 24.5 +0.25 = \boxed{-12}



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