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bija089 [108]
3 years ago
7

Evaluate the permutation. 6P2 15 30 36

Mathematics
1 answer:
dolphi86 [110]3 years ago
5 0

Answer:

30

Step-by-step explanation:

Using the definition

nP_{r} = \frac{n!}{(n-r)!}

where n ! = n(n - 1)(n - 2)(n - 3)... × 3 × 2 × 1

Thus

6P_{2} = \frac{6!}{4!} = \frac{6.5.4.3.2.1}{4.3.2.1} ← cancel 4.3.2.1 on numerator/ denominator, leaving

      = 6 × 5

      = 30

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Which of the following is equivalent to the expression below sqrt 8 - sqrt 72 + sqrt 50
mash [69]

Answer:

Step-by-step explanation:

\sqrt{8}-\sqrt{72}+\sqrt{50} These cannot combine the way they are. The rule for adding and subtracting radicals is really picky. Not only does the index have to be the same (the little number that is sitting outside in the bend of the radical {ours is a 2, which isn't usually there, but is instead understood to be a square root}), but the radicand, the expression under the square root (or cubed root, or fourth root, etc) has to the same as well. All of our radicals are square roots, so that's good, but the radicands are all different. The first one is an 8, the next one is a 72, and the last one is a 50. BUT if we can rewrite them by simplifying them and then the radicands are the same, we're in good shape.

Simplify by taking the prime factorization of each of those numbers.

8: 4*2 and 4 is a perfect square, so we'll stop there

72: 36*2 and 36 is a perfect square, so we'll stop there

50: 25*2 and 25 is a perfect square, so we'll stop there.

Now, rewrite each one of them in terms of their prime factorization:

\sqrt{4*2}-\sqrt{36*2}+\sqrt{25*2} and then pull out each perfect square as its root:

2\sqrt{2}-6\sqrt{2}+5\sqrt{2} and now all the radicands are the same, so we can add them to get

1\sqrt{2}  or simply  \sqrt{2}

6 0
3 years ago
Read 2 more answers
Simplify square root of 2 over cube root of 2.
Fed [463]

Answer:

2 to the power of one sixth

Step-by-step explanation:

Assuming you don't already know this, any type of root can be expressed as an exponent. Generally speaking:

\sqrt[n]{x}  =  {x}^{ \frac{1}{n} }

So you can rewrite the given fraction as

\frac{ {2}^{ \frac{1}{2} } }{ {2}^{ \frac{1}{3} } }

and then reduce as you normally would. That is, if the bases of the numerator and denominator are the same, then you can subtract the denominator's exponent from the numerator's exponent like so:

\frac{ {2}^{ \frac{1}{2} } }{ {2}^{ \frac{1}{3} } }  =  {2}^{ \frac{1}{2} -  \frac{1}{3}  }

Since

\frac{1}{2}  -  \frac{1}{3}  =  \frac{3}{6}  -  \frac{2}{6}  =  \frac{1}{6}

the answer is

{2}^{ \frac{1}{6} }  \: or \:  \sqrt[6]{2}

3 0
3 years ago
Read 2 more answers
Factor 5(2x+7)+4(2x+7)<br>enter your answer in the box​
AfilCa [17]

Answer:

18x+63

Step-by-step explanation:

First you've to simplfy it, multiply the first bracket by 5 and the second by 4.

= (5)(2x)+(5)(7) + (4)(2x)+(4)(7)

= 10x+35+8x+28

Combine Like Terms:

= 10x+35+8x+28

= (10x+8x)+(35+28)

= 18x+63

6 0
3 years ago
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The area of rectangular field is (49m2-42m+9).Find the dimensions of the field
Drupady [299]

Answer:

The dimensions are (7m-3) by (7m-3)

Step-by-step explanation:

We have the area of the rectangular field to be:

49 {m}^{2}  - 42m + 9

We need to factorize this expression.

Let us rewrite to obtain:

{(7m)}^{2}  - 2(7 \times 3)m +  {3}^{2}

We can easily see that the expression is actually a perfect square trinomial.

This gives us:

(7m - 3)^{2}

Or

(7m - 3)(7m - 3)

6 0
3 years ago
Answer please........
Likurg_2 [28]

you have to show the graph

4 0
3 years ago
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