Question

Evaluate the permutation. 6P2 15 30 36

Answer 1

Answer:

30

Step-by-step explanation:

Using the definition

n$P_{r}$ = $\frac{n!}{(n-r)!}$

where n ! = n(n - 1)(n - 2)(n - 3)... × 3 × 2 × 1

Thus

6$P_{2}$ = $\frac{6!}{4!}$ = $\frac{6.5.4.3.2.1}{4.3.2.1}$ ← cancel 4.3.2.1 on numerator/ denominator, leaving

      = 6 × 5

      = 30