Evaluate the permutation. 6P2 15 30 36

Mathematics

1 answer:

dolphi86 [110]3 years ago

5 0

Answer:

Step-by-step explanation:

Using the definition

n $P_{r}$ = $\frac{n!}{(n-r)!}$

where n ! = n(n - 1)(n - 2)(n - 3)... × 3 × 2 × 1

Thus

6 $P_{2}$ = $\frac{6!}{4!}$ = $\frac{6.5.4.3.2.1}{4.3.2.1}$ ← cancel 4.3.2.1 on numerator/ denominator, leaving

= 6 × 5

= 30

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