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alexdok [17]
3 years ago
13

Sean and Rachel we’re both born on April 17.

Mathematics
1 answer:
ipn [44]3 years ago
5 0

Step-by-step explanation:

let Sean be 4 years old and Rachel be 2 years old on April 17

part (A)

R=S-2 --(A)

is an equation that can be used to determine Rachel's age

likewise,

S=R+2--(B)

can be used to determine Sean's age

part (B)

use equation(A) for table (1) and equation(B) for table 2

Table (1) : R=S-2=11-2= R=9

12-2=10=»R=10

13-2=11=»R=11

14-2=12=»R=12

15-2=13=»R=13

16-2=15=»R=14

likewise use equation B for the table (2)

the outputs must be 3,4,5,6,7,8

and 9

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Roger the park ranger was standing in a look out tower that was 200 ft tall. Looks down, sees a fire. Angle of depression is 7 d
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Answer:

approx. 24.6 ft

Step-by-step explanation:

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Using these values you can draw a diagram that highlights that you need to use trig. to work out the answer.

Using Tan:

Tan 7=x/200 ft

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Answer:

(6\sqrt{3},\,\frac{5\pi}{6})

Step-by-step explanation:

The radius  r  can be found from the relationship

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The point is in Quadrant II (-, +), so use the inverse cosine function to find the angle.

\cos{\theta}=\frac{x}{r}=\frac{-9}{6\sqrt{3}}\\\cos{\theta}=-\frac{9}{6\sqrt{3}} \cdot \frac{\sqrt{3}}{\sqrt{3}}\\\cos{\theta}=-\frac{9\sqrt{3}}{6\cdot3}\\\cos{\theta}=-\frac{\sqrt{3}}{2}\\\\\cos^{-1}\frac{-\sqrt{3}}{2}}=\frac{5\pi}{6}

See the attached image.

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Answer:

Answer

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6 0
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Read 2 more answers
One pound of swordfish costs as much as 1.5 pounds of salmon. Mrs. O pays $39 for 2 pounds of salmon and 3 pounds of swordfish.
Dimas [21]

Answer:

The ratio of the amount for swordfish to the amount of salmon is 6:4

Step-by-step explanation:

Given as :

The price for 1 pound of swordfish = The price of 1.5 pound of salmon

So, On this relation

The price for ( 1 × 2 ) pound of swordfish = The price of ( 1.5× 2 )  pound of salmon

i.e The price for 2 pound of swordfish = The price of 3 pound of salmon

Now According to question

Mrs. O pay the total money for 2 pounds of swordfish and 3 pound of salmon = $ 39

Let the money she pay for swordfish = 2 sw

And The money she pay for salmon = 3 sa

∵, The total money she pay for both  = $ 39

I.e  2 sw + 3 sa = 39

As 2 sw = 3 sa

So, 3 sa + 3 sa = 39

Or, 6 sa = 39

or, sa = \frac{39}{6} = \frac{13}{2}

∴ sw = \frac{13}{2} × \frac{3}{2}

or, sw = \frac{39}{4}

Now, the ratio of the amount for swordfish to the amount of salmon = \frac{\frac{39}{4}}{\frac{13}{2}}

I.e The ratio = \frac{6}{4}

Hence The ratio of the amount for swordfish to the amount of salmon is 6:4

Answer

3 0
3 years ago
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