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4 years ago

Can someone please explain this

Mathematics

1 answer:

SSSSS [86.1K]4 years ago

4 0

Answer:

-1

Step-by-step explanation:

can you also hep me on something

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If x = -2, then x 2-7x+10 equals <br> a. 0 <br> b.20 <br> c.28

sveta [45]

ANSWER

C. 28

EXPLANATION

The given expression is

${x}^{2} - 7x + 10$

We want to evaluate this function at x=-2.

We just have to substitute x=-2 into the given expression.

In other words, we have to replace x with -2 wherever we see x in the expression

${( - 2)}^{2} - 7( - 2) + 10$

We evaluate the exponent to get

$4 - 7( - 2) + 10$

We multiply next to get:

$4 + 14+ 10$

We now add to obtain:

$28$

The correct answer is C

6 0

3 years ago

Pumping stations deliver oil at the rate modeled by the function D, given by d of t equals the quotient of 5 times t and the qua

goblinko [34]

<h2>Hello!</h2>

The answer is: There is a total of 5.797 gallons pumped during the given period.

To solve this equation, we need to integrate the function at the given period (from t=0 to t=4)

The given function is:

$D(t)=\frac{5t}{1+3t}$

So, the integral will be:

$\int\limits^4_0 {\frac{5t}{1+3t}} \ dx$

So, integrating we have:

$\int\limits^4_0 {\frac{5t}{1+3t}} \ dt=5\int\limits^4_0 {\frac{t}{1+3t}} \ dx$

Performing a change of variable, we have:

$1+t=u\\du=1+3t=3dt\\x=\frac{u-1}{3}$

Then, substituting, we have:

$\frac{5}{3}*\frac{1}{3}\int\limits^4_0 {\frac{u-1}{u}} \ du=\frac{5}{9} \int\limits^4_0 {\frac{u-1}{u}} \ du\\\\\frac{5}{9} \int\limits^4_0 {\frac{u-1}{u}} \ du=\frac{5}{9} \int\limits^4_0 {\frac{u}{u} -\frac{1}{u } \ du$

$\frac{5}{9} \int\limits^4_0 {(\frac{u}{u} -\frac{1}{u } )\ du=\frac{5}{9} \int\limits^4_0 {(1 -\frac{1}{u } )$

$\frac{5}{9} \int\limits^4_0 {(1 -\frac{1}{u })\ du=\frac{5}{9} \int\limits^4_0 {(1 )\ du- \frac{5}{9} \int\limits^4_0 {(\frac{1}{u })\ du$

$\frac{5}{9} \int\limits^4_0 {(1 )\ du- \frac{5}{9} \int\limits^4_0 {(\frac{1}{u })\ du=\frac{5}{9} (u-lnu)/[0,4]$

Reverting the change of variable, we have:

$\frac{5}{9} (u-lnu)/[0,4]=\frac{5}{9}((1+3t)-ln(1+3t))/[0,4]$

Then, evaluating we have:

$\frac{5}{9}((1+3t)-ln(1+3t))[0,4]=(\frac{5}{9}((1+3(4)-ln(1+3(4)))-(\frac{5}{9}((1+3(0)-ln(1+3(0)))=\frac{5}{9}(10.435)-\frac{5}{9}(1)=5.797$

So, there is a total of 5.797 gallons pumped during the given period.

Have a nice day!

4 0

4 years ago

The soccer net in Peter's back yard is 5 1/2 feet high, but only 4 feet wide. Jill's soccer net is also 5 1/2 feet high, but is

Black_prince [1.1K]

The area of Jill's soccer net is 3 times larger than area of Peter's soccer net.

<h3> Area of Peter's soccer net</h3>

The area of Peter's soccer net is determined by using area of rectangle as shown below;

A1 = 5.5 ft x 4 ft

A1 = 22 ft²

<h3> Area of Jill's soccer net</h3>

A2 = 5.5 ft x 12 ft

A2 = 66 ft²

<h3>Ratio of the area of their soccer net</h3>

A2/A1 = 66/22

A2/A1 = 3

Thus, the area of Jill's soccer net is 3 times larger than area of Peter's soccer net.

Learn more about area of rectangle here: brainly.com/question/25292087

4 0

2 years ago

Rearrange the formula C = 2πr for r.

Oliga [24]

R=<span>C/2π

cheers
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year 9?</span>

6 0

4 years ago

Read 2 more answers

28=−4x+5−x−2<br> what is X?

goblinko [34]

Answer:

X= -5

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers