1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
muminat
3 years ago
8

Why is 1.095 less than 1.95

Mathematics
1 answer:
Alex3 years ago
3 0

Answer:

it's less then

Step-by-step explanation:

because one and ninety-five thousandths are ten times as smaller than one and ninety-five hunderdths and hunderdths is closer to the decimal than the thousandth. undersand now?

You might be interested in
Write the composite function in the form f(g(x)). [Identify the inner function u = g(x) and the outer function y = f(u).] y = ta
Irina-Kira [14]

Answer:

The inner function is u = \pi x.

The outer function is f(u) = \tan{u}.

\frac{dy}{dx} = y^{\prime} = \sec^{2}(u)*\pi = \pi\sec^{2}{\pi x}

Step-by-step explanation:

The inner function is the one we apply the outer function to.

So

y = \tan{\pi x}

We apply the outer function tangent to \pi x.

So, the inner function is u = \pi x.

The outer function is f(u) = \tan{u}.

The derivative of a compositve function

y = f(u) in which u = g(x) is given by the following function.

y^{\prime} = f^{\prime}(u)*g^{\prime}(x)

So

f(u) = \tan{u}

f^{\prime}(u) = \sec^{2}{u}

u = g(x) = \pi x

g^{\prime}(x) = \pi

So

y^{\prime} = f^{\prime}(u)*g^{\prime}(x)

\frac{dy}{dx} = y^{\prime} = \sec^{2}(u)*\pi = \pi\sec^{2}{\pi x}

7 0
2 years ago
A rectangle’s base is 6 cm longer than its height. The rectangle’s area is 135 cm2. Find this rectangle’s dimensions. You must i
il63 [147K]

Area of a rectangle  =  length x height

Area = 135

Height = X

Lenght = x +6

135 = x * x+6

Simplify:

135 = x^2 +6x

Subtract 135 from both sides:

x^2 + 6x - 135 = 0

Solve:

2 numbers when added need to equal 6 and when multiplied equal -135

x = 9 and x = -15

The height can't be a negative number so the height is 9

Length =  9 +6 = 15

Height = 9cm, Length = 15 cm

6 0
3 years ago
Yumi and Juan pick up litter along the highway at the same rate. Yumi picks up litter for 3 miles and takes two hours longer tha
Harlamova29_29 [7]

3/(x+2) = 2/x

multiply both fractions by x(x+2) to cancel out the bottoms

so it becomes 3x = 2x+4

ow subtract 2X from both sides and you get

x = 4

so it took Juan 4 hours

 it took Yumi 2 hours more so 4+2 = 6 hours

7 0
3 years ago
Read 2 more answers
One side of triangle is 4cm longer than the shortest side and 2cm shorter than the longest side the perimeter is 38cm what are t
o-na [289]
9.3, 13.3, 15.3
Hope it helps!
7 0
3 years ago
Read 2 more answers
Raj is 3 inches taller than Howared. Let h represent Howards height. write an algebraic expression to represent Raj's height.
Nitella [24]
Answer:
Let's say Raj's height is 60 inches
60-3 = H
H= Howard's height
60 = Raj's height
Or it could be with two variables
R-3 = H
R = Raj's height
4 0
2 years ago
Other questions:
  • Betsy made ribbons for school spirit day. Her roll was 30 ft. Long. For each individual ribbon she needed 0.625 ft. How many rib
    12·1 answer
  • PLEASE HELP 15 POINTS!!
    6·1 answer
  • Brock is a plumber. He charges a flat rate of $40 to visit a house to inspect it's plumbing. He charges an additional $20 for ev
    15·2 answers
  • The number in the middle of a data set best describes
    8·1 answer
  • A counterexample proves why a statement is true<br> A. True<br> B.false
    12·2 answers
  • HELP HURRY PLEASEEEEEEEEEEEEE
    14·2 answers
  • Altitude vs. speed equations
    5·1 answer
  • Assume that the college in Offer #1 has a Cost of Attendance of $73,332. Which of the statements below comparing Offer #1 to Off
    14·1 answer
  • Name the property shown by each statement.
    10·2 answers
  • The coordinates of the points P, Q and R are given by (-2, 1), (1, 4) and (4, k) respectively. Find the value(s) of k if
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!