Diffusion is a process that results from the random motion of molecules and results in a net movement of matter from a high-concentration region to a low-concentration zone.
In this compound (Phosgene) the central atom (carbon is Sp² Hybridized).
Sp, Sp² and Sp³ can be calculated very simply by doing three steps,
Step 1:
Assume triple bond and double bond as one bond and assign s or p to it. In this example carbon double bond oxygen is considered once and let suppose it is s. Now we are having our s.
Step 2:
Count lone pair of electron, each lone pair counts for s and p. In this case there is no lone pair of electron on carbon, so not included.
Step 3:
Count single bonds for s and p. As we have already assigned s to the double bond, now one p for one single bond, and other p for the other single bond.
Result:
So, we counted 1 s for double bond, 1 p for one single and other p for second single bond. As a whole we got,
Sp²
Practice:
You can practice for hybridization of Oxygen in this molecule. Oxygen has 2 lone pair of electrons. (Hint: Sp² Hybridization)
Answer:
Le Chatelier's principle predicts that equilibrium will shift to decrease the concentration of reactants. Increasing the rate of the forward reaction will mean a decrease in reactants. ... When the concentration of reactants is increased, the equilibrium shifts to the right and there will be more product than before.
Answer:
Option D.
Explanation:
Some of the alpha particles Rutherford shot at the gold foil bounced back, some scattered; but the majority of them went right through. That meant there had to be some sort of positively charged subatomic particle in there that pulled them through, but it had to be at the center and couldn't take up a lot of room.
