Answer:
2.16 moles of Au₂S₃ are decomposed.
Explanation:
Given data:
Number of moles of gold (III) sulfide decomposed = ?
Number of moles of gold metal formed = 4.32 mol
Solution:
Chemical equation:
Au₂S₃ → 2Au + 3S
Now we will compare the moles of Au₂S₃ with gold metal.
Au : Au₂S₃
2 : 1
4.32 : 1/2×4.32 = 2.16
2.16 moles of Au₂S₃ are decomposed.
Answer:
the ratio would be 1:2:1
Explanation:
since it is C6 H12 O6
12 is double of 6 so it would be 2
and 6 is considered 1
False. gases have to greatest freedom of motion
2
C
4
H
10
(
g
) + 13
O
2
(
g
) = 8
C
O
2
(
g
) + 10
H
2
O
(
g
)
values of the quantum numbers: -6,-5,-4,-3,-2,-1,0,1,2,3,4,5,6
location of the electron: In the 7th energy level away from the nucleus.
Explanation:
From the description of the problem, the magnetic number is given is as -6,-5,-4,-3,-2,-1,0,1,2,3,4,5,6 and the electron is located in the 7th energy level away from the nucleus. Basically, the problem is testing for the understanding of the principal quantum numbers which gives the location of electrons and the magnetic quantum number that shows the spatial orientation of the orbitals.
The orbital designation of the describe electron is 7d
- Magnetic quantum number is limited by the azimuthal quantum number which is the quantum number describing the possible shapes. The azimuthal is given as L= n-1. "n" is the principal quantum number which is 7. Therefore L is 6 and the magnetic quantum numbers are -6,-5,-4,-3,-2,-1,0,1,2,3,4,5,6
- The position of the electron is given by the principal quantum number which represents the main energy level in which the orbital is located or the average distance from the nucleus. Here it is 7.
Learn more:
brainly.com/question/9288609
#learnwithBrainly
