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vlada-n [284]
3 years ago
8

Which pair shares the same empirical formula?

Chemistry
1 answer:
kolezko [41]3 years ago
3 0

Answer: A. C_2H_2 and C_6H_6

Explanation: Empirical formula is the formula which shows the elements of a compound in the simplest ratio of atoms and not the actual number of atoms as shown in molecular formula.

A) C_2H_2 and C_6H_6 : Empirical formula for  C_2H_2 is CH and C_6H_6 is CH

B) C_2H_2 and C_2H_4: Empirical formula for  C_2H_2 is CH and C_2H_4 is CH_2

C) CH_2 and C_6H_6: Empirical formula for  CH_2 is CH_2 and C_6H_6 is CH

D) CH and C_2H_4: Empirical formula for  CH is CH and C_2H_4 is CH_2


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Answer:

365 days and five hours

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Which of the following are testable?<br> hypotheses<br> laws<br> theories
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Hypothesis and theory
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: An unknown metal crystallizes in the cubic crystal structure. The metal has a radius 140pm, atomic mass of 135 g/mol, and dens
ki77a [65]

The cubic unit cell  this metal crystallize as is BCC structure .

<h3> What is unit cell ?</h3>

The structure of a crystalline solid, whether a metal or not, is best described by considering its simplest repeating unit, which is referred to as its unit cell.

The unit cell consists of lattice points that represent the locations of atoms or ions.

The entire structure then consists of this unit cell repeating in three dimensions

\rm \rho =\dfrac{nM}{N_{0} a^{3}} \\\\\\\\\rm n =\dfrac{\rho N_{0} a^{3}}{M} \\\\\\\\Assuming\; it \; to \; be \; a\; BCC\; structure \\\\\\ r = \dfrac{\sqrt{3} \times a}{4} \\\\\\Therefore\; a = 3.23 \times 10^{-8}\\\\\\\\\rm n =\dfrac{13.3 \times 6.022 \times 10^{23}\times 3.23^{3}\times (10^{-8})^{3}}{135} \\\\

n= 2

Hence our assumption was correct

It is a BCC structure .

Therefore the cubic unit cell  this metal crystallize as is BCC structure .

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5 0
2 years ago
A solution is prepared by mixing 50.0 mL toluene (C6H5CH3 d=0.867 g/mL) with 125 mL Benzene (C6H6 d=0.874 g/mL). Assuming that t
Tatiana [17]

Answer:

mass % = 28.4%

mole fraction = 0.252

molality = 3.08 molal

molarity = 2.69 M

Explanation:

Step 1: Data given

Volume of toluene = 50.0 mL = 0.05 L

Density toluene = 0.867 g/mL

Molar mass toluene = 92.14 g/mol

Volume of benzene = 125 mL = 0.125 L

Density benzene = 0.874 g/mL

Molar mass benzene = 78.11 g/mol

Step 2: Calculate masses

Mass = density * volume

Mass toluene = 50.0 mL * 0.867 g/mL = 43.35 g

Mass benzene = 125 mL * 0.874 g/mL = 109.25 g

Step 3: Calculate number of moles

Moles = mass / molar mass

Moles toluene = 43.35 grams /92.14 g/mol = 0.470 5 moles

Moles benzene = 109.25 grams / 78.11 g/mol = 1.399 moles

Step 4: Calculate molarity of toluene

Molarity = moles / volume

Molarity toluene = 0.4705 moles / 0.175 L = 2.69 M

Step 5: Calculate mass % of toluene

Mass % = (43.35 grams / (43.35 + 109.25) )*100 % = 28.4 %

Step 6: Calculate mole fraction of toluene

Mole fraction toluene = Moles toluene / total number of moles

Mole fraction toluene = 0.4705 / (0.4705 + 1.399) = 0.252

Step 7: Molality of toluene

Molality = number of moles / mass

Molality of toluene = 0.4705 moles / (0.04335 + 0.10925)

Molality of toluene = 3.08 molal

4 0
3 years ago
What is the suffix for -<br>✯ Alcohols<br>✯ Ketones<br>✯ Halogens<br><br>thankyou ~​
antoniya [11.8K]

Answer:

ane, al, keto

ol, al, keto

ol, al, one

ol, ane, one.

Explanation:

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Functional group is a ketone, therefore suffix = -one

Hydrocarbon structure is an alkane therefore -ane

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pentan-2-one or 2-pentanone

CH3CH2CH2C(=O)CH3

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