Solution :
A cell that is concentrated is constructed by the same half reaction for the anode as well as he cathode.
We know,
In a standard cell,
the reduction half cell reaction is :
![$Ag^+(aq)+e^- \rightarrow Ag(s) E^0 = -0.80 \ V$](https://tex.z-dn.net/?f=%24Ag%5E%2B%28aq%29%2Be%5E-%20%5Crightarrow%20Ag%28s%29%20E%5E0%20%3D%20-0.80%20%5C%20V%24)
The oxidation half ell reaction :
![$Ag(s) \rightarrow Ag^+(aq) + e^- \ E^0= +0.80 \ V$](https://tex.z-dn.net/?f=%24Ag%28s%29%20%5Crightarrow%20Ag%5E%2B%28aq%29%20%2B%20e%5E-%20%5C%20E%5E0%3D%20%2B0.80%20%5C%20V%24)
Thus the complete reaction of the cell is :
![$Ag^+(aq)+ Ag(s) \rightarrow Ag^+(aq)+Ag(s)$](https://tex.z-dn.net/?f=%24Ag%5E%2B%28aq%29%2B%20Ag%28s%29%20%5Crightarrow%20Ag%5E%2B%28aq%29%2BAg%28s%29%24)
cell = ![$E_R - E_L = 0.00 \ \text{volts}$](https://tex.z-dn.net/?f=%24E_R%20-%20E_L%20%3D%200.00%20%20%5C%20%5Ctext%7Bvolts%7D%24)
Can you show the question that goes with those answer pls
Answer: The correct answer is option E
Explanation:
Sodium/potassium pump is a mechanism that involves the movement of sodium ions (Na+) out of a cell and potassium ions (K+) into a cell, thereby regulating concentration of ions on both sides of a typical cell membrane.
In this situation, the sodium-potassium pump is usually helps in the establishment of the resting potential. The potassium voltage channels normally closes before the membrane potential is brought to a resting level.
In summary, sodium/potassium pump helps to maintain a balance in the system.
<u>11.35 g</u><u> </u><u>atoms </u><u>of lead are in the sample.</u>
What does density mean?
- The density of an area refers to the quantity of things—which may include people, animals, plants, or objects—there are in it.
- Divide the number of objects by the area's measurement to determine density.
- A country's population density is calculated by dividing its total population by its area, expressed in square kilometers or miles.
We can calculate the volume of the cube by cubing the side of the cube.
Volume of cube = ( 1.000 cm)³
= 1.000 cm³
We can now determine the amount of lead in the cube by multiplying by the density. Because we know we have a 1.000 cubic centimeter and that lead has a density of 11.35 grams per cubic centimeter, we have 11.35 grams of lead.
= ( 1.000 cm³) ( 11.35
)
= 11.35 g
Learn more about density
brainly.com/question/15164682
#SPJ4