With 11 electrons how many electron shells does sodium have?
1 answer:
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The concentration in /mmolL of the chemist's silver(I) nitrate solution is 0.01047 mmoles/litre.
Explanation:
Data given:
Number of moles of AgNO3 in micro mole 4.7102micromol.
The concentration is supposed to be in mmol so the micromole will be converted to milimole.
So, 1 micromole = 0.001 millimole
hence, 4.712micromole will be 0.004712 millimole.
Volume is given as 450ml which is converted into L
to convert ml into L it is divided by 1000
so 0.45 L is the volume.
Molarity or concerntration is calculated by the formula,
molarity =
putting the values in the formula:
molarity =
= 0.01047 mmoles/litre is the molarity of AgNO3 solution in 450 ml of solution.
The question is incomplete, here is the complete question:
Consider the reaction
Initially, = 3.60 M; at equilibrium
. Calculate the equilibrium concentration for
<u>Answer:</u> The equilibrium concentration of ammonia is 2.8 M
<u>Explanation:</u>
We are given:
Initial concentration of = 3.60 M
Initial concentration of = 3.60 M
For the given chemical equation:
Initial: 3.60 3.60
At eqllm: 3.60-4x 3.60-7x 2x 6x
We are given:
Equilibrium concentration of = 0.60 M
Evaluating the value of 'x'
So, equilibrium concentration of
Hence, the equilibrium concentration of ammonia is 2.8 M