3 years ago

an object exerts a force of 10 N on an area of 2 square meters. what is the pressure the object exerts on the surface?

1 answer:

motikmotik3 years ago

5 0

Pressure = Force/Area

P = 10 / 2 N/m²

P = 5 N/m²

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frosja888 [35]

Solution

Given data

According to Boyle's law, PV = K

The required general equation thus is

$\begin{gathered} p_1v_1=p_2v_2 \\ p_1=? \\ p_2=\text{ 8.25 atm} \\ v_2=1,645ml \\ v_1=7450ml \end{gathered}$

Substituting these values we find that the initial pressure is

$\begin{gathered} p_1\times7450\text{ = 8.25 }\times1645 \\ p_1=\frac{13571.25}{7450} \\ p_1=1.82164\text{atm} \\ p_1\approx1.8atm \end{gathered}$

The initial pressure to the nearest tenth, therefore, is 1.8 atm.

The final answer, therefore, is Option D

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