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Alinara [238K]
3 years ago
7

A ball is fixed to the end of a string which is attached to the ceiling at point P. As the drawing shows, the ball is projected

downward at A with the lunch speed Vo. Traveling on a circular path, the ball comes to a halt at point B. What enables the ball to reach point B, which is above point A. Ignore friction and air resistance. a. The balls initial kinetic energy. b. The balls initial gravitational potential energy. c. The work done by the tension in the string. d. The work done by the gravitational force.
Physics
1 answer:
sergiy2304 [10]3 years ago
5 0

Answer:

a. The balls initial kinetic energy.

Explanation:

As we know that initially speed is given to the ball downwards so that it moved in a circle so then finally reached to point B

Now given that point B is higher than the initial position A from which it is projected

Now by energy conservation we know that

K_i + U_i = K_f + U_f

since final speed is zero so we have

K_i + mgh_a = 0 + mgh_b

h_b = h_a + \frac{K_i}{mg}

so from above equation we can say that since initial kinetic energy is given to the ball so it will be able to reach the point which is higher than its initial position

so correct answer is

a. The balls initial kinetic energy.

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The average Intensity of the electromagnetic field due to sunlight at the surface of the earth is 1400 W/m^2. Calculate the maxi
Ann [662]

Answer:

1027 N/C

3.42 x 10⁻⁶ T

Explanation:

I = Intensity of electromagnetic field = 1400 W/m²

E₀ = Maximum value of electric field

Intensity of electromagnetic field is given as

I = (0.5) ε₀ E₀² c

1400 =  (0.5) (8.85 x 10⁻¹²) (3 x 10⁸) E₀²

E₀ = 1027 N/C

B₀ = maximum value of magnetic field

using the equation

E₀ = B₀ c

1027 = B₀ (3 x 10⁸)

B₀ = 3.42 x 10⁻⁶ T

4 0
3 years ago
0.250 moles of gas are in a piston.The gas does 109 J of work while 240 J of heat are added. What is the change in internal ener
irina [24]

Answer:

+131Joules

Explanation:

Energy can be expressed using below expresion.

ΔE = (q + w).........eqn(1)

q will be + be if heat is gained hence, q= 240 J

work "w" will be - ve if work is done by the system, hence w= -109 J

Then substitute into eqn(1)

Change in Internal energy=

= (240 -109 )

= +131J

6 0
3 years ago
When Trinity pulls on the rope with her weight, Newton's Third Law of Motion tells us that the rope will _____.
Grace [21]
The rope will pull back against you.
5 0
3 years ago
Read 2 more answers
Calculate the approximate volume of a uranium nucleus, 23592u. (you can ignore the mass defect in this calculation and simply ta
tester [92]

Radius of nuclei is given by formula

R = R_oA^{1/3}

now we can say volume of the nuclei is given as

V = \frac{4}{3}\pi R_o^3* A

now the density is given as

density = mass / volume

mass of nuclei = mass of neutron + mass of protons

m = z*m_p + (A- z)*m_n

m_p = m_n = 1.008u

m = A*1.008u

Now density is given as

\rho = \frac{A*1.008u}{\frac{4}{3}\pi R_0^3* A}

here we know that

R_0 = 1.2 fm

\rho = \frac{1.008u}{\frac{4}{3}\pi*(1.2*10^{-15})^3}

\rho = 2.31 * 10^{17} kg/m^3

So from above we can say that density of all nuclei is almost same.

5 0
3 years ago
Aconstant current of 3 Afor 4 hours is required to charge an automotive battery. If the terminal voltage is V, where t is in hou
kirza4 [7]

Answer:

(a) 43.2 kC

(b) 0.012V kWh

(c) 0.108V cents

Explanation:

<u>Given:</u>

  • i = current flow = 3 A
  • t = time interval for which the current flow = 4\ h = 4\times 3600\ s = 14400\ s
  • V = terminal voltage of the battery
  • R = rate of energy = 9 cents/kWh

<u>Assume:</u>

  • Q = charge transported as a result of charging
  • E = energy expended
  • C = cost of charging

Part (a):

We know that the charge flow rate is the electric current flow through a wire.

\therefore i = \dfrac{Q}{t}\\\Rightarrow Q =it\\\Rightarrow Q = 3\times 14400\\\Rightarrow Q = 43200\ C\\\Rightarrow Q = 43.200\ kC\\

Hence, 43.2 kC of charge is transported as a result of charging.

Part (b):

We know the electrical energy dissipated due to current flow across a voltage drop for a time interval is given by:

E = Vit\\\Rightarrow E = V\times 3\times 4\\\Rightarrow E = 12V\ Wh\\\Rightarrow E = 0.012V\ kWh\\

Hence, 0.012V kWh is expended in charging the battery.

Part (c):

We know that the energy cost is equal to the product of energy expended and the rate of energy.

\therefore \textrm{Cost}=\textrm{Energy}\times \textrm{Rate}\\\Rightarrow C = ER\\\Rightarrow C = 0.012V\times 9\\\Rightarrow C =0.108V\ cents

Hence, 0.108V cents is the charging cost of the battery.

4 0
4 years ago
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