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Nana76 [90]
2 years ago
5

2. Stars normally convert hydrogen into helium through nuclear fusion. That requires incredibly hot temperatures and high pressu

re. At the moment, the temperature of empty space is nowhere near warm enough to fuse any elements together. What type of temperature and pressure conditions needed to be present in the early universe in order to create the first hydrogen atoms
Physics
1 answer:
jolli1 [7]2 years ago
6 0

Answer:

About 4,000 K and 10⁻¹⁷ atm

Explanation:

The Big Bang theory states that the Big Bang which is the origin of the universe was about 13.75 billion years ago, and the temperature a few seconds later was 10³²K

The first element began forming at about 3 minutes after the Big Bang with a temperature of 10⁹ K, the nuclei of simple elements

The nuclei of hydrogen and helium began combine with electrons at a temperature of 3,000 K to 4,000 K to form the first neutral atoms. The pressure of the universe at that stage was 10⁻¹⁷ atmospheres

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To simulate deafness, put ear plugs or cotton balls into your ears and put your hands over your ears to block out all sound. Des
yulyashka [42]

Just so you know, total deafness is quite different than partial deafness.

Partial deafness can be any number of things. It can be an inability to make out the contents of high notes (notes with high frequencies and few harmonics).

Partial deafness can be the inability to hear low notes. I only know one person who suffers from that.

Your response to speech is quite different. Usually you have to have people look right at you. Lip reading is an art. Most deaf people between what they partially hear and lip reading can make out about 1/2 of what is said. Guessing usually takes care of the rest. Course you can get everything all muddled by guessing.

It does change your way of life. The TV is often turned up high enough that people living 4 houses down can list to the 6 o'clock news when you do.

Music is hard to make out. The overtones are lost.

Earphones have very tinny sound.

People are not as enjoyable as they once were.

6 0
2 years ago
What is the speed of sound in solid? <br>​
sasho [114]
The speed of sound in a solid would be 6000 metres per second
7 0
2 years ago
Read 2 more answers
Which statement defines an ore? Rock broken down to become part of the topsoil. Rock dug out from the earth to use in constructi
Anika [276]

Rock dug out from the deep inside earth and refined.

Explanation:

Ores are usually rocks dug out from deep within the earth and refined.

An ore is an aggregate of metalliferous minerals with gangue that can be won at profit under current economic conditions.

Ores are rocks and rocks can be ores if they contain viable economic minerals.

They are usually naturally formed and they contain different minerals.

For example cassiterite is a known ore of tin.

Learn more:

Rocks brainly.com/question/2817889

#learnwithBrainly

5 0
2 years ago
Read 2 more answers
A hollow cylinder of mass 2.00 kg, inner radius 0.100 m, and outer radius 0.200 m is free to rotate without friction around a ho
Aneli [31]

Answer:

h=2.86m

Explanation:

In order to give a quick response to this exercise we will use the equations of conservation of kinetic and potential energy, the equation is given by,

\Delta PE_i + \Delta KE_i = \Delta PE_f +\Delta KE_f

There is no kinetic energy in the initial state, nor potential energy in the end,

mgh+0=0+KE_f

In the final kinetic energy, the energy contributed by the Inertia must be considered, as well,

mgh = (\frac{1}{2}mv^2+\frac{1}{2}I\omega^2)

The inertia of the bodies is given by the equation,

I=\frac{m(R_1^2+R^2_2)}{2}

I=\frac{2(0.2^2+0.1^2)}{2}

I=0.05Kgm^2

On the other hand the angular velocity is given by

\omega =\frac{v}{R_2}=\frac{4}{1/5} = 2rad/s

Replacing these values in the equation,

(0.5)(9.8)(h) =\frac{1}{2}*0.5*4^2+\frac{1}{2}*0.05*20^2

Solving for h,

h=2.86m

5 0
2 years ago
Tammy leaves the office, drives 34 km due north, then turns onto a second highway and continues in a direction of 35◦ north of e
Natasha2012 [34]

Answer:

The total displacement is 102 km 51^o north of east.

Explanation:

We can treat this problem as a trigonometric one, so we need to calculate the total displacement on the north and east.

d_n=34km+79km*sin(35^o)=79km

and

d_e=79*cos(35^o)=65km

The total displacement is given by:

D=\sqrt{(79km)^2+(65km)^2}=102km

with an agle of:

\alpha =arctg(\frac{79km}{65km})=51^o

4 0
2 years ago
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