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Stels [109]
3 years ago
11

You hold a piece of wood in one hand and a piece of iron in the other. both pieces have the same volume, and you hold them fully

under water at the same depth. at the moment you let go of them, which one experiences the greater buoyancy force?
Physics
1 answer:
aivan3 [116]3 years ago
5 0
You hold a piece of wood in one hand and a piece of iron in the other. Both pieces have the same volume, and you hold them fully under water at the same depth. At the moment you let go of them, which one experiences the greater buoyancy force?<span>
</span>
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The player that possess the best ball handling skills and usually handles the ball often
velikii [3]

The player that possess the best ball handling skills and usually handles

the ball often is referred to as the point guard.

Point guards in basketball are referred to as the players who have certain

characteristics such as speed ,an excellent ball handling skills and

leadership qualities.

Point guards is similar to the creative midfielder in soccer which helps to

dictate play and create chances for other team mates which is why they

handle the ball often.

Read more on brainly.com/question/25759951

4 0
3 years ago
How much energy is required to accelerate a golf ball of mass 0.046 kg initially at rest to a speed of 0.75c?
Andrew [12]

The required energy to accelerate the golf ball is  0.232875X10^{16} kg-m/sec^2.

<h2>What is Energy?</h2>
  • Energy, which is observable in the execution of labor as well as in the form of light and heat, is the quantitative quality that is transmitted to an object or to a physical phenomenon in physics.
  • Energy is a preserved resource; according to the rule of conservation of energy, energy can only be transformed from one form to another and cannot be created or destroyed.
  • The joule, which is defined as "the energy transmitted to an object by the effort of moving it a length of one metre against a force of one newton," is the standard measure for power in the International System of Units (SI).

Given that,

E=mc^2

=0.046X0.75^2Xc^2

=0.232875X10^{16} kg-m/sec^2 .

Learn more about energy here:

brainly.com/question/13881533

#SPJ4

3 0
2 years ago
The work-energy theorem states that a force acting on a particle as it moves over a ______ changes the ______ energy of the part
svetoff [14.1K]

Answer:

B. distance/potential

Explanation:

Quizlet

5 0
3 years ago
A charge of 25 nC is uniformly distributed along a straight rod of length 3.0 m that is bent into a circular arc with a radius o
Greeley [361]

Answer:

E = 31.329 N/C.

Explanation:

The differential electric field dE at the center of curvature of the arc is

dE = k\dfrac{dQ}{r^2}cos(\theta ) <em>(we have a cosine because vertical components cancel, leaving only horizontal cosine components of E. )</em>

where r is the radius of curvature.

Now

dQ = \lambda rd\theta,

where \lambda is the charge per unit length, and it has the value

\lambda = \dfrac{25*10^{-9}C}{3.0m} = 8.3*10^{-9}C/m.

Thus, the electric field at the center of the curvature of the arc is:

E = \int_{\theta_1}^{\theta_2} k\dfrac{\lambda rd\theta  }{r^2} cos(\theta)

E = \dfrac{\lambda k}{r} \int_{\theta_1}^{\theta_2}cos(\theta) d\theta.

Now, we find \theta_1 and \theta_2. To do this we ask ourselves what fraction is the arc length  3.0 of the circumference of the circle:

fraction = \dfrac{3.0m}{2\pi (2.3m)}  = 0.2076

and this is  

0.2076*2\pi =1.304 radians.

Therefore,

E = \dfrac{\lambda k}{r} \int_{\theta_1}^{\theta_2} cos(\theta)d\theta= \dfrac{\lambda k}{r} \int_{0}^{1.304}cos(\theta) d\theta.

evaluating the integral, and putting in the numerical values  we get:

E = \dfrac{8.3*10^{-9} *9*10^9}{2.3} *(sin(1.304)-sin(0))\\

\boxed{ E = 31.329N/C.}

4 0
3 years ago
Why does the sample on a microscope slide need to be very thin?
ziro4ka [17]

B. so light can shine through it from below.

4 0
3 years ago
Read 2 more answers
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