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3 years ago

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You hold a piece of wood in one hand and a piece of iron in the other. both pieces have the same volume, and you hold them fully

under water at the same depth. at the moment you let go of them, which one experiences the greater buoyancy force?

1 answer:

aivan3 [116]3 years ago

5 0

You hold a piece of wood in one hand and a piece of iron in the other. Both pieces have the same volume, and you hold them fully under water at the same depth. At the moment you let go of them, which one experiences the greater buoyancy force?<span>
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A dock worker applies a constant horizontal force of 80.5 N to a block of ice on a smooth horizontal floor. The frictional force

Eddi Din [679]

Answer:

(a). The mass of the block of ice is 62.8 kg.

(b). The distance is 24.192 m.

Explanation:

Given that,

Horizontal force = 80.5 N

Distance = 13.0 m

Time = 4.50 s

(a). We need to calculate the acceleration of the block of ice

Using equation of motion

$s=ut+\dfrac{1}{2}at^2$

Put the value into the formula

$13=0+\dfrac{1}{2}\times a\times(4.50)^2$

$a=\dfrac{13\times2}{(4.50)^2}$

$a=1.28\ m/s^2$

We need to calculate the mass of the block of ice

Using formula of force

$F = ma$

$m=\dfrac{F}{a}$

Put the value into the formula

$m=\dfrac{80.5}{1.28}$

$m=62.8\ kg$

(b). If the worker stops pushing at the end of 4.50 s,

We need to calculate the velocity

Using equation of motion

$v =u+at$

Put the value into the formula

$v=0+1.28\times4.50$

$v=5.76\ m/s$

We need to calculate the distance

Using formula of distance

$v = \dfrac{d}{t}$

$d=v\times t$

Put the value into the formula

$d=5.76\times4.20$

$d=24.192\ m$

Hence, (a). The mass of the block of ice is 62.8 kg.

(b). The distance is 24.192 m.

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3 years ago

Under state law, what is the blood-alcohol limit for legally operating a motor vehicle?

Ymorist [56]

Answer:

HOPE IT HELPS....

Explanation:

CORRECT ANSWER IS 0.08

THANK YOU,

PLZ MARK ME AS BRAINLIST

5 0

3 years ago

Tom has two pendulums with him. Pendulum 1 has a ball of mass 0.2 kg attached to it and has a length of 5 m. Pendulum 2 has a ba

mars1129 [50]

Given Information:

Pendulum 1 mass = m₁ = 0.2 kg

Pendulum 2 mass = m₂ = 0.6 kg

Pendulum 1 length = L₁ = 5 m

Pendulum 2 length = L₂ = 1 m

Required Information:

Affect of mass on the frequency of the pendulum = ?

Answer:

The mass of the ball will not affect the frequency of the pendulum.

Explanation:

The relation between period and frequency of pendulum is given by

f = 1/T

The period of pendulum is given by

T = 2π√(L/g)

Where g is the acceleration due to gravity and L is the length of the string

As you can see the period (and frequency too) of pendulum is independent of the mass of the pendulum. Therefore, the mass of the ball will not affect the frequency of the pendulum.

Bonus:

Pendulum 1:

T₁ = 2π√(L₁/g)

T₁ = 2π√(5/9.8)

T₁ = 4.49 s

f₁ = 1/T₁

f₁ = 1/4.49

f₁ = 0.22 Hz

Pendulum 2:

T₂ = 2π√(L₂/g)

T₂ = 2π√(1/9.8)

T₂ = 2.0 s

f₂ = 1/T₂

f₂ = 1/2.0

f₂ = 0.5 Hz

So we can conclude that the higher length of the string increases the period of the pendulum and decreases the frequency of the pendulum.

3 0

3 years ago

Read 2 more answers

A closed container initially holds 50 monatomic Aparticles that have a combined energy of 480 units. After 100 monatomic B parti

Molodets [167]

Answer:

"8 units" is the appropriate answer.

Explanation:

According to the question,

Throughout equilibrium all particles are of equivalent intensity, and as such the integrated platform's total energy has been uniformly divided across all individuals.

Now,

The total energy will be:

= $480+720$

= $1200 \ units$

The total number of particles will be:

= $50+100$

= $150$

hence,

Energy of each A particle or each B particle will be:

= $\frac{1200}{150}$

= $8 \ units$

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3 years ago

You know the power for a machine and the time it takes to produce that power, what value can you calculate?

Sati [7]

We can calculate the work done by the machine by the mathematical formula,

P = W/t

where, P = Power

W = work done

t = time

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3 years ago