Louise used this figure to model the expression 20 divided by 4.

An orange cone has a exact volume of 120π ft³. What is the height of the cone if the radius is 6ft?

Ber [7]

Answer:

10 ft

Step-by-step explanation:

Given:

Radius ⇒ 6 feet
Formula of cone ⇒ V = 1/3πr²h

Plug in the values given:

120π=1/3π(6²)h

Cancel π from both sides and simplify:

120 = 1/3 36h
120 = 12h

Answer:

Height = 10

4 0

2 years ago

The length of a screw produced by a machine is normally distributed with a mean of 0.75 inches and a standard deviation of 0.01

White raven [17]

99.7%
You can use normalCdf(.72,.78,.75,.01) to find the answer or if you standardize your numbers (z scores) normalCdf(-3,3,0,1).

6 0

3 years ago

Read 2 more answers

How to solve 3x-2y, at x=-4 and y=2

Elza [17]

Answer:

8y

Step-by-step explanation:

8y

8 0

3 years ago

Can I get some help im stuck???

svetoff [14.1K]

Connor
Initial Value=200ft
Rate of Change=10ft/min

Pilar
Initial Value=242ft
Rate of Change=8ft/min

6 0

3 years ago

A data set with a mean of 34 and a standard deviation of 2.5 is normally distributed

tresset_1 [31]

Answer:

a) $z= \frac{34-34}{2.5}= 0$

$z= \frac{39-34}{2.5}= 2$

And we want the probability from 0 to two deviations above the mean and we got 95/2 = 47.5 %

b) $P(X$

$z= \frac{31.5-34}{2.5}= -1$

So one deviation below the mean we have: (100-68)/2 = 16%

c) $z= \frac{29-34}{2.5}= -2$

$z= \frac{36.5-34}{2.5}= 1$

For this case below 2 deviation from the mean we have 2.5% and above 1 deviation from the mean we got 16% and then the percentage between -2 and 1 deviation above the mean we got: (100-16-2.5)% = 81.5%

Step-by-step explanation:

For this case we have a random variable with the following parameters:

$X \sim N(\mu = 34, \sigma=2.5)$

From the empirical rule we know that within one deviation from the mean we have 68% of the values, within two deviations we have 95% and within 3 deviations we have 99.7% of the data.

We want to find the following probability:

$P(34 < X$

We can find the number of deviation from the mean with the z score formula:

$z= \frac{X -\mu}{\sigma}$

And replacing we got

$z= \frac{34-34}{2.5}= 0$

$z= \frac{39-34}{2.5}= 2$

And we want the probability from 0 to two deviations above the mean and we got 95/2 = 47.5 %

For the second case:

$P(X$

$z= \frac{31.5-34}{2.5}= -1$

So one deviation below the mean we have: (100-68)/2 = 16%

For the third case:

$P(29 < X$

And replacing we got:

$z= \frac{29-34}{2.5}= -2$

$z= \frac{36.5-34}{2.5}= 1$

For this case below 2 deviation from the mean we have 2.5% and above 1 deviation from the mean we got 16% and then the percentage between -2 and 1 deviation above the mean we got: (100-16-2.5)% = 81.5%

7 0

3 years ago