Answer:
x = -36, y = 6, z = -6
Step-by-step explanation:
The requirement x/z = -z means x = -z².
The requirement x/y = z means x = yz.
These two requirements together mean yz = -z², or y = -z.
The requirements that z/2 and z/3 are integers mean that z is a multiple of 2·3 = 6. The smallest magnitude non-zero multiple is z=-6 (since we also require z < -z).
Using z=-6, we have x = -z² = -36; y = -(-6) = 6.
For some positive integer n, ...
... x = -36n², y = 6n, z = -6n.
Answer:
Step-by-step explanation:
Answer:
C = 12 + 15(x - 4)
C = 15x - 48
Step-by-step explanation:
Let the number of hours = t
The total amount Miguel earns =
C
To edit a manuscript, Miguel charges 12 dollars per hour for the first 4 hours and 15 dollars per hour after the first 4 hours.
C = 12 + 15(x - 4)
Expand the t
C = 12 + 15x - 60
C = 15x - 48
Therefore, an expression for the amount, in dollars, Miguel charges if it takes him t hours to edit a manuscript, where t>4 is given as:
C = 15x - 48
Answer:
Step-by-step explanation:
6v + 12b = 504 eq1
2v + 5b = 204 eq2
6v + 15b = 612 eq2 times 3
0 -3b = 504 - 612 subtraction of the two bolded eqs
-3b = -108 solve for b
b = 36
Another way to solve the problem
6v + 12b = 504 I would eliminate the v term by multiplying the bottom
2v + 5b = 204 equation by -3 on BOTH sides and then add the two eqs
2v + 5b = 204
-3(2v + 5b) = -3(204)
-6v - 15b = -612
6v + 12b = 504
-6v - 15b = -612 add the like terms
(6v + (-6v)) + (12b + (-15b) = 504 + (-612)
(6v -6v)) + (12b - 15b) = 504 - 612)
0 + -3b = - 108 solve for b divide both sides by -3
b = -108/-3
b = 36
use eq 2v + 5b = 204 to solve for v and knowing b = 36
2v + 5b = 204 b=36
2v + 5(36) = 204 substract 5 times 36 from both sides
2v = 204 - 180
v = 24 / 2
v = 12
NOW CHECK the values for b and v using the OTHER eq
6v + 12b = 504
6(12) + 12(36) = 504
72 + 432 = 504
504 = 504 IT CHECKS
Is it for greatest common factor or least common factor
