1. -12n-20
2. 3-15k
3. 15p-15
4.-8+11d
5.17-42n
Answer: Fourth option: y^2=9^2+19^2-2(9)(19) cos(41°)
The law of cosines to solve for one side is:
c^2=a^2+b^2-2ab cos C
We must know the other two sides (a and b) and the angle between these sides (angle C, the opposite to the side that we want to determine)
In this case c=y, a=9, b=19, and C=41°, then:
y^2=9^2+19^2-2(9)(19) cos (41°)
Answer:
See explanation
Step-by-step explanation:
If PK and PF are tangent to the circle, then the radii OK and OF are perpendicular to the lines PK and PF respectively.
Consider quadrilateral PFOK. The sum of the measures of all interior angles in quadrilateral PFOK is equal to 360°. Since OK and OF are perpendicular to the lines PK and PF, you have that
∠FOK+90°+∠KPF+90°=360°,
∠FOK=360°-90°-90°-∠KPF=180°-∠KPF.
Angles FOK and KOE are supplementary angles, then
∠KOE=180°-∠FOK=180°-(180°-∠KPF)=∠KPF.
Since angle KOE is central angle, the arc EK has the same measure as angle KOE and as angle KPF.
Answer:
8 * 7 = 3 * 18
Simplifying
8 * 7 = 3 * 18
Multiply 8 * 7
56 = 3 * 18
Multiply 3 * 18
56 = 54
Solving
56 = 54
Step-by-step explanation:
