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Aleks04 [339]
3 years ago
15

How to write repeating 3.01 as a mixed number

Mathematics
1 answer:
stepan [7]3 years ago
7 0
3.010101.. = 3 + 0.010101... = 3 + 1/(100 - 1) = 3 + 1/99 = 3 1/99
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Help me please and if you do, I will add you and give you brainliest
lorasvet [3.4K]

Answer: B

Step-by-step explanation:

7 0
3 years ago
How do I solve this equation?
umka2103 [35]

Answer:

3 / 512

Step-by-step explanation:

If you want to simplify further, reduce the exponents:

2²/2¹⁰ + 2²/2¹¹

1/2⁸ + 1/2⁹

Find the common denominator and add.

2/2⁹ + 1/2⁹

3/2⁹

3/512

7 0
4 years ago
What is the average of 22.10;13.45;25.10;17.20;19.10?
Oxana [17]

The correct answer is: 19.39

Explanation:

Given numbers:

22.10, 13.45, 25.10, 17.20, 19.10

Total numbers = 5

Average = \frac{Sum-of-all-numbers}{total-numbers}

Now to find the average of the given sequence, follow these steps:

Step-1:

Add all the numbers to get the total sum:

22.10 + 13.45 + 25.10 + 17.20 + 19.10 = 96.95

Step-2:

Divide 96.95 by 5 to get the average number:

\frac{96.95}{5} = 19.39

Hence the correct answer is 19.39.

6 0
3 years ago
Read 2 more answers
According to a study in a medical journal, 202 of a sample of 5,990 middle-aged men had developed diabetes. It also found that m
tekilochka [14]

Answer:

0.0588 = 5.88% probability that a middle-aged man with diabetes is very active

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Has diabetes.

Event B: Is very active.

Probability of having diabetes:

To find this probability, we take in consideration that:

It also found that men who were very active (burning about 3,500 calories daily) were a fourth as likely to develop diabetes compared with men who were sedentary. Assume that one-fifth of all middle-aged men are very active, and the rest are classified as sedentary.

So the probability of developing diabetes is:

x of 4/5 = x of 0.8(not active)

x/4 = 0.25x of 1/5 = 0.2(very active). So

P(A) = 0.8x + 0.25*0.2x = 0.85x

Probability of developing diabetes while being very active:

0.25x of 0.2. So

P(A \cap B) = 0.25x*0.2 = 0.05x

What is the probability that a middle-aged man with diabetes is very active?

P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.05x}{0.85x} = \frac{0.05}{0.85} = 0.0588

0.0588 = 5.88% probability that a middle-aged man with diabetes is very active

4 0
3 years ago
Ashley calculates her salary (vase and commission) for the year y using a model y = 0.2x + 25,000; where x represents her total
finlep [7]

<em>Answer:</em>

<em>A)</em>

<em>Step-by-step explanation:</em>

<em>The y-intercept represents Ashleys base play</em>

<em>Best,</em>

<em>SunflowerJada</em>

4 0
3 years ago
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