Hello,
Answer A
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The 3rd one is correct, you would put a compass on Point P and draw a small arc on lIne NO on each side of Point P, then place the compass on the line at those points and draw arcs above and below P then connect those points with a ruler.
H (x) = 5x^2+40x+64
y = (5x^2+40x+60) + 4
y = 5(x^2+8x+12) + 4
y = 5(x+2)(x+6) + 4
y-4 = 5(x+2)(x+6)
This means that the solutions, or where the parabola crosses the x-axis, are at x+2=0 and x+6=0, or x=-2, -6
So the midpoint of -2 and -6 is -4, the axis of symmetry is x=-4
Answer: our fruitful chance
Step-by-step explanation:
