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myrzilka [38]
3 years ago
10

How does friction slow things down?

Physics
2 answers:
Lapatulllka [165]3 years ago
8 0
Friction slows things down because the tiny rough bumps on all surfaces hook on each other and slow down the object and produce heat
Ymorist [56]3 years ago
5 0
Friction slows things down because the force that is created through the interaction between two objects begins to decrease the acceleration and velocity of the object. Therefore, the object begins to slow down. 
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A 500-g lump of clay is dropped onto a 1-kg cart moving at 60 cm/s. The clay is moving downward at 30 cm/s just before l dith t
viktelen [127]

Answer:

The speed of the cart and clay after the collision is 50 cm/s .

Explanation:

Given :

Mass of lump , m = 500 g = 0.5 kg .

Velocity of lump , v = 30 cm/s .

Mass of cart , M = 1 kg .

Velocity of cart , V = 60 cm/s .

We know by conservation of momentum :

mv+MV=(m+M)v'

Here , v' is the speed of the cart and clay after the collision .

Putting all value in above equation .

We get :

0.5\times 30+1\times 60=(0.5+1)\times v'\\\\v'=\dfrac{15+60}{1.5}\\\\v'=50\ cm/s

Hence , this is the required solution .

3 0
3 years ago
Assuming all object are moving with the same velocity, witch statement describes the object with the largest intertia?
Kisachek [45]

Answer:

Mass is the quantitative measure of inertia of any object.

Explanation:

The object that have largest mass will   have largest inertia as well as largest momentum.

3 0
3 years ago
2. Which of the following wavelength properties would require a stopwatch to measure?
katovenus [111]

Answer:

<u><em>A. wavelength</em></u>

Explanation:

The others are about sound and how high it is. That has nothing to do with time.

3 0
3 years ago
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Exercising helps reduce?
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Answer:

stress,depression and anxiety by improving self esteem.

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3 years ago
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A 3.0 kg box is sliding along a frictionless horizontal surface with a speed of 1.8 m/s when it encounters a spring. (a) Determi
krok68 [10]

Answer:

a) k = 2231.40 N/m

b) v = 0.491 m/s

Explanation:

Let k be the spring force constant , x be the compression displacement of the spring and v be the speed of the box.

when the box encounters the spring, all the energy of the box is kinetic energy:

the energy relationship between the box and the spring is given by:

1/2(m)×(v^2) = 1/2(k)×(x^2)

    (m)×(v^2) = (k)×(x^2)

a) (m)×(v^2) = (k)×(x^2)

                 k = [(m)×(v^2)]/(x^2)

                 k = [(3)×((1.8)^2)]/((6.6×10^-2)^2)

                 k = 2231.40 N/m

Therefore, the force spring constant is 2231.40 N/m

b) (m)×(v^2) = (k)×(x^2)

             v^2 = [(k)(x^2)]/m

                 v =  \sqrt{ [(k)(x^2)]/m}

                 v = \sqrt{ [(2231.40)((1.8×10^-2)^2)]/(3)}

                    = 0.491 m/s

8 0
3 years ago
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