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777dan777 [17]
3 years ago
6

During maneuvers preceding the Battle of Jutland, the British battle cruiser Lion moved as follows (in nautical miles): 1.2 mile

s north, 6.1 miles 38 degrees east of south, 4.0 miles at 89 degrees east of north, and 6.5 miles at 31 degrees east of north. Find the distance between starting and ending positions. (Ignore the earth’s curvature.)
Physics
1 answer:
lana66690 [7]3 years ago
5 0

Answer:

total distance is 11.3 miles

Explanation:

Given data:

distance to north = 1.2 miles

distance to south at 38 degree east of south = 6.1 miles  

distance to east of north at angle 89 degree = 4 miles  

distance to east of north at angle 31 degree =  6.5 miles

considering each displacement as vector so we have

\begin{pmatrix}0.0\\  1.2\end {pmatrix}   + \begin {pmatrix}3.8\\  -4.8\end{pmatrix} +\begin{pmatrix}4.0\\  0.1\end {pmatrix}+\begin{pmatrix}3.3\\  5.6\end{pmatrix} = \begin{pmatrix}11.1\\  2.1\end{pmatrix}

total distance is \sqrt{11.1^2 + 2.1^2} \approx  11.3

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A 50.0-kg projectile is fired at an angle of 30 degrees above thehorizontal with an initial speed of 1.20 x 102 m/s fromthe top
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a)  Em₀ = 42.96 104 J , b)   W_{fr} = -2.49 105 J , c)  vf = 3.75 m / s

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The negative sign indicates that the work that force and displacement have opposite directions

c) In this case the work of the friction going up is already calculated in part b and the work of the friction going down would be 1.5 that job

We have that the work of friction is equal to the change of mechanical energy

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       -1.5 2.49 10⁵ = ½ m vf² - 42.96 10⁴

       ½ m vf² = -1.5 2.49 10⁵ + 4.296 10⁵

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