Please help, only answer if your 1000% correct im in summer school and need to pass this class
2 answers:
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Answer:
C. 8.4 × 10^2 volts
Explanation:
The potential energy of a charge is given by:
where
q is the magnitude of the charge
V is the electric potential
In this problem, we have
is the charge
is the potential energy
Re-arranging the formula and using these numbers, we can find the electric potential:
Answer:
x = 9.32 cm
Explanation:
For this exercise we have an applied torque and the bar is in equilibrium, which is why we use the endowment equilibrium equation
Suppose the counterclockwise turn is positive, let's set our reference frame at the left end of the bar
- W l / 2 - W_{child} x + N₂ l = 0
x = 1)
now let's use the expression for translational equilibrium
N₁ - W - W_(child) + N₂ = 0
indicate that N₂ = 4 N₁
we substitute
N₁ - W - W_child + 4 N₁ = 0
5 N₁ -W - W_{child} = 0
N₁ = ( W + W_{child}) / 5
we calculate
N₁ = (450 + 250) / 5
N₁ = 140 N
we calculate with equation 1
x = -250 1.50 + 4 140 3) / 140
x = 9.32 cm