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Mariana [72]
3 years ago
15

Please help, only answer if your 1000% correct im in summer school and need to pass this class

Physics
2 answers:
Marianna [84]3 years ago
6 0

because they work on the same object

Explanation:

A push and pull factor

swat323 years ago
4 0
1) they act on different objects
2)push or pull action
3) (no image so i cant answer this sorry)
4)the force of the ball against the bat
5)Newton’s first law
6)newtons third law
7)there are unequal forces acting on the object
8)(no image again sorry)
9)(no image)
10)newtons second law
11)all of the above
12) f=ma
A= f/m = 870/
Mass wasnt provided so i cant solve this
13)they act on different objects
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mars1129 [50]
This is the answer to Question 5

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3 years ago
Equation of motion description is v=20+2t.How big is the initial speed,acceleration?
trasher [3.6K]

Answer:

the initial velocity is 20 m/s   and  the acceleration is 2 m/s²

Explanation:

Given equation of motion, v = 20 + 2t

If V represents the final velocity of the object, then the initial velocity and acceleration of the object is calculated as follows;

From first kinematic equation;

v = u + at

where;

v is the final velocity

u is the initial velocity

a is the acceleration

t is time of motion

If we compare  (v = u + at)   to     (v = 20 + 2t)

then, u = 20    and  

         a = 2

Therefore, the initial velocity is 20 m/s   and  the acceleration is 2 m/s²

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3 years ago
A train travels 160 km in 2 h. What is the train’s average speed in km/h?
loris [4]
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3 years ago
In a charging process, 4 × 1013 electrons are removed from one small metal sphere and placed on a second identical sphere. Initi
Alina [70]

Answer:

The distance between the two spheres is 914.41 X 10³ m

Explanation:

Given;

4 X 10¹³ electrons, and its equivalent in coulomb's is calculated as follows;

1 e = 1.602 X 10⁻¹⁹ C

4 X 10¹³ e = 4 X 10¹³ X 1.602 X 10⁻¹⁹ C = 6.408 X 10⁻⁶ C

V = Ed

where;

V is the electrical potential energy between two spheres, J

E is the electric field potential between the two spheres N/C

d is the distance between two charged bodies, m

V = \frac{K*q}{d^2}*d = \frac{K*q}{d}

d = \frac{K*q}{V}

where;

K is coulomb's constant = 8.99 X 10⁹ Nm²/C²

d = (8.99 X 10⁹ X 6.408 X 10⁻⁶)/0.063

d = 914.41 X 10³ m

Therefore, the distance between the two spheres is 914.41 X 10³ m

3 0
3 years ago
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