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likoan [24]
3 years ago
5

Find the length l of one "arch" of this cycloid, that is, find the distance traveled by a small stone stuck in the tread of a ti

re of radius r during one revolution of the rolling tire.
Physics
2 answers:
Evgesh-ka [11]3 years ago
4 0

Answer: L = 2*R*π

Explanation: Considering the case where no other forces or effects are happening (Sliding, deformation, etc) The path that the rock does inside of a circular object is equal to the perimeter of the circular object, in this case, a rolling tire.

Then if the radius of the tire is R; the perimeter of the tire is equal to:

p = 2*R*π  

And for one revolution of the tire, the length of the arc that the rock travels is equal to the perimeter; so we have:

L = P = 2*R*π

Marat540 [252]3 years ago
3 0

If there is no slipping or skidding going on, then for each revolution, the tire rolls along the ground a distance equal to the tire's circumference.

Circumference of the tire = 2 · π · Radius .

During the same revolution, the small stone stuck in the tread travels in a big semicircular arc that's  <em>(2 · π · r)</em> long.  (roughly 6.28r)

 

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Which of the following is an example of acceleration?
kompoz [17]

Answer:

B) a leaf blown from a tree by the wind

6 0
3 years ago
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a van moves with a constant speed of 79 km/h how long will it take to travel a distance of 502 kilometers
Mazyrski [523]

Answer:

6.35hours

Explanation:

s=vt

t=s/v=502/79=6.35hours

5 0
3 years ago
Imagine holding a basketball in both hands, throwing it straight up as high as you can, and then catching it when it falls. At w
Alisiya [41]

Answer:

C. At the instant the ball reaches its highest point.

Explanation:

When a body is thrown up, it tends to come down due to the influence of gravitational force acting on the body. The body will be momentarily at rest at its maximum point before falling. At this maximum point, the velocity of the body is zero and since force acting on a body is product of the mass and its acceleration, the force acting on the body at that point will be "zero"

Remember, F = ma = m(v/t)

Since v = 0 at maximum height

F = m(0/t)

F = 0N

This shows that the force acting on the body is zero at the maximum height.

4 0
3 years ago
A catcher in a baseball game stops a pitched ball that was originally moving at 44 m/s over a distance of 12.5 cm. the mass of t
eduard

Answer:

Force = -1161.6 Newton

Explanation:

Given the following data;

Initial velocity, u = 44m/s

Distance ,s = 12.5cm to m = 12.5/100 = 0.125m

Mass = 0.15kg

To find the acceleration;

We would use the third equation of motion;

V ² = U² + 2as

0² = 44² + 2*a*0.125

0 = 1936 + 0.25a

0.25a = -1936

a = -1936/0.25

Acceleration, a = -7744m/s2

Force = mass * acceleration

Substituting into the equation, we have;

Force = 0.15 * (-7744)

Force = -1161.6 Newton

The value of its force is negative because the glove decreases the velocity of the ball.

4 0
3 years ago
A cat jumps from 2.5-meter-tall bookshelf to a 1.3-meter-tall countertop. If the cat
UkoKoshka [18]

The change in Potential energy of the cat is 176.4 J.

<h3 /><h3>Potential Energy:</h3>

This is the energy due to the position of a body. The S.I unit is Joules (J)

The formula for change in potential energy.

<h3 /><h3>Formula:</h3>
  • ΔP.E = mg(H-h).............. Equation 1

<h3>Where:</h3>
  • ΔP.E = Change in potential energy
  • m = mass of the cat
  • g = acceleration due to gravity
  • H = First height
  • h = second height.

From the question,

<h3>Given:</h3>
  • m = 15 kg
  • H = 2.5 m
  • h = 1.3 m
  • g = 9.8 m/s²

Substitute these values into equation 1

  • ΔP.E = 15×9.8(2.5-1.3)
  • ΔP.E = 15×9.8×1.2
  • ΔP.E = 176.4 J.

Hence, The change in Potential energy of the cat is 176.4 J

Learn more about Potential energy here: brainly.com/question/1242059

5 0
2 years ago
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