Find the length l of one "arch" of this cycloid, that is, find the distance traveled by a small stone stuck in the tread of a ti
2 answers:
You might be interested in
Answer:
Explanation:
Parameters given:
Charge of object, q = 5 mC =
Acceleration of object, a =
Mass of object, m = 2.0 g
The Electric field exerts a particular force on the object, causing it to accelerate (Electrostatic force).
We know that Electrostatic force, F, is given in terms of Electric field, E, as:
F = qE
This means that the object exerts a force of -qE on the Electric force (Action with equal and opposite reaction).
The object also has a force, F, due to its acceleration a. This force is the product of its mass and acceleration. Mathematically:
F = ma
Equating the two forces of the object, we get:
-qE = ma
=>
Solving for E, we have:
The magnitude will be:
The electric field has a magnitude of 0.002 N/C.
Explanation:
Given that,
Mass if the rock, m = 1 kg
It is suspended from the tip of a horizontal meter stick at the 0-cm mark so that the meter stick barely balances like a seesaw when its fulcrum is at the 12.5-cm mark.
We need to find the mass of the meter stick. The force acting by the stone is
F = 1 × 9.8 = 9.8 N
Let W be the weight of the meter stick. If the net torque is zero on the stick then the stick does not move and it remains in equilibrium condition. So, taking torque about the pivot.
W = 3.266 N
The mass of the meters stick is :
So, the mass of the meter stick is 0.333 kg.