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monitta
2 years ago
9

Find the measure of

Mathematics
2 answers:
Goryan [66]2 years ago
5 0
What are you talking about
san4es73 [151]2 years ago
3 0
Find the measure of what?
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Russia has recently started a push for stronger smoking regulations much like those in western countries concerning cigarette ad
Blababa [14]

Answer:

a) 0.46

b) (2341.39, 3230.61)

c) For those Russians who do smoke, estimate the number of cigarettes smoked per day.= 23

Step-by-step explanation:

check below for more detailed solution

7 0
3 years ago
I need help please and thank you!!!
Komok [63]

Answer:

what do you want to find?

4 0
2 years ago
Read 2 more answers
The trace of an n×n matrix A, denoted tr(A), is thesum of its diagonal entries; that is,tr(A) = a11 + a22 +· · ·+annShow that(a)
Ulleksa [173]

Answer:

Step-by-step explanation:

for two matrices A, B to be Similar, then A = SBS⁻¹

A=SBS−1⟹trace(A)=trace((SB)(S−1))=trace((S−1)(SB))=trace((SS−1)B)=trace(B)

4 0
3 years ago
Select the conic section that represents the equation. x2 - y2 = 16
Mariana [72]

x^2-y^2=16 represents a hyperbola.

8 0
3 years ago
Zachary has nickels, dimes and quarters in his piggy bank. He has 58 coins with a total value of $6.50. There are twice as many
kari74 [83]

Answer:

nickel = 16

dimes = 32

quarters = 10

Step-by-step explanation:

Given that,

number of coins Zachery have in his piggy bank = 58

total money Zachery have in his piggy bank = $6.50

Suppose number of nickel = x

               number of dimes = 2x

               number of quarters = y

1 nickel = $0.05

1 dime = $0.10

1 quarter = $0.25

<h3>Equation 1</h3>

x + 2x + y = 58

3x + y = 58

<h3>Equation 2</h3>

x(0.05) + 2x(0.10) + y(0.25) = 6.50

0.05x + 0.2x + 0.25y = 6.50

0.25x + 0.25y = 6.50

y = 58 - 3x

<h3>put value of y in equation 2</h3>

0.25x + 0.25(58 - 3x) = 6.50

0.25x + 14.5 - 0.75x = 6.50

-0.5x = 6.50 - 14.5

-0.5x = -8

x = 16

y = 58 - 3x

y = 58 -3(16)

y =10

number of nickel = x = 16

number of dimes = 2x = 32

number of quarters = y = 10

5 0
3 years ago
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