2X^2+4X-8-X^2+6X-4
X^2+4X-8+6X-4
X^2+10X-12
Answer:
LHS.= Sin 2x /( 1 + cos2x )
We have , sin 2x = 2 sinx•cosx
And. cos2x = 2cos^2 x - 1
i.e . 1+ cosx 2x = 2cos^2x
Putting the above results in the LHSwe get,
Sin2x/ ( 1+ cos2x ) =2 sinx•cosx/2cos^2x
=sinx / cosx
= Tanx
.•. sin2x/(1 + cos2x)= tanx
Step-by-step explanation:
Answer:
$55
Step-by-step explanation:
its $150 - $40 = $110
$110 / 2 = $55
Answer:
Step-by-step explanation:
412
