Can someone help me please?
1 answer:
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The correct answer is: [D]: " (-5 
)x − 
" .
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Explanation:
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" -1/2(-3/2x + 6x + 1) −<span> 3x " ;
= (-1/2 * -3/2 x) + (-1/2 * 6x) + (-1/2 * 1) </span>− <span>3x ;
= [ (-1 *-3) /(2*2)] x + (-3x) + (-1/2) ] </span>− <span>3x ;
= [ (3/4)x </span>− 3x − (1/2) ] −<span> 3x ;
= </span>(3/4)x − 3x − (1/2) − 3x ;
= ?? ; → Combine the "like terms" ;
→ "(3/4)x − 3x − 3x " = ?? ;
→ "(3/4)x − 3x = "(-9/4)x";
→ "(-9/4)x − 3x = "(-21/4)x " = " (-5)x " ;
→ The answer is: " (-5)x − " ;
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→ which is:
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→ Answer choice: [D]: " (-5)x − " .
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_________________________________________________________
Explanation:
_________________________________________________________
" -1/2(-3/2x + 6x + 1) −<span> 3x " ;
= (-1/2 * -3/2 x) + (-1/2 * 6x) + (-1/2 * 1) </span>− <span>3x ;
= [ (-1 *-3) /(2*2)] x + (-3x) + (-1/2) ] </span>− <span>3x ;
= [ (3/4)x </span>− 3x − (1/2) ] −<span> 3x ;
= </span>(3/4)x − 3x − (1/2) − 3x ;
= ?? ; → Combine the "like terms" ;
→ "(3/4)x − 3x − 3x " = ?? ;
→ "(3/4)x − 3x = "(-9/4)x";
→ "(-9/4)x − 3x = "(-21/4)x " = " (-5
→ The answer is: " (-5
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→ which is:
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→ Answer choice: [D]: " (-5
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This equation has the next form:
To find if the equation has two complex solutions we have to check if the discriminant is negative, as follows:
Then, the first case has two complex solutions.
In the second case,
The discriminant in this case is:
Then, the second case has two complex solutions.
In the third case,
The discriminant in this case is:
Then, the third case has two real solutions.
In the fourth case,
The discriminant in this case is:
Then, the fourth case has two complex solutions.