Answer:
Redundancy
Req. 1 and Req. 3 are seemed to say the same thing. We need to remove the first sentence in Req. 1
Conflict and understandability
Req. 1 states that access is through web browser while Req. 4 states that access is via html. We have to re-write the Req. 3 to make it clear that users do not actually have to write directly html to communicate with the system.
Completeness
Req. 5 states that print out will “mainly” be documents. What else might be printed? What other inputs will be produced?
Either remove mainly or clarify other print out.
What version of html or web browser is assumed in Req. 1 and Req. 3?
Explanation:
<span>d. select information is sent to the search engines database to be indexed. </span>
Answer:
The program written in C++ is as follows'
#include<iostream>
using namespace std;
int main()
{
string names[3];
cout<<"Please enter three names: "<<endl;
for (int i = 0; i< 3;i++)
{
cin>>names[i];
}
for (int i = 2; i>= 0;i--)
{
cout<<names[i]<<endl;
}
return 0;
}
Explanation:
This line declares an array for 3 elements
string names[3];
This line prompts user for three names
cout<<"Please enter three names: "<<endl;
This following iteration lets user input the three names
for (int i = 0; i< 3;i++) { cin>>names[i]; }
The following iteration prints the three names in reverse order
for (int i = 2; i>= 0;i--) { cout<<names[i]<<endl; }
Answer:
876100
019343
Explanation:
10s complement of a decimal number is obtained by the following process:
- Obtain 9s complement ( Subtract each digit by 9)
- Add 1 to the result
1) 123900
9s complement => (9-1)(9-2)(9-3)(9-9)(9-0)(9-0)
= 876099
Adding 1 , 10s complement of 123900 = 876100
2) 980657
9s complement = (9-9)(9-8)(9-0)(9-6)(9-5)(9-7)
= 019342
Adding 1 , 10s complement of 980657 = 019343
Answer:
class studentType: public personType
{
public:
virtual void print() = 0;
virtual void calculateGPA() = 0;
void setID(long id) {
studentId = id;
}
void setCourses(const string c[], int noOfC) {
noOfCourses = noOfC;
for (int i=0; i<noOfCourses; i++) {
courses[i] = c[i];
}
}
void setGrades(const char cG[], int noOfC) {
noOfCourses = noOfC;
for (int i=0; i<noOfCourses; i++) {
coursesGrade[i] = cG[i];
}
}
long getID() {
return studentId;
}
string* getCourses() {
return courses;
}
char* getGrades() {
return coursesGrade;
}
studentType(string fName = "", string lastName = "",
long id = 0, string c[] = NULL, char cG[] = NULL, int noOfC = 0);
private:
long studentId;
string courses[6];
char coursesGrade[6];
int noOfCourses;
};
Explanation:
Code rewritten
