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2 years ago

Write a program that asks the user for three names, then prints the names in reverse order.

Computers and Technology

1 answer:

sasho [114]2 years ago

8 0

Answer:

The program written in C++ is as follows'

#include<iostream>

using namespace std;

int main()

{

string names[3];

cout<<"Please enter three names: "<<endl;

for (int i = 0; i< 3;i++)

{

cin>>names[i];

}

for (int i = 2; i>= 0;i--)

{

cout<<names[i]<<endl;

}

return 0;

}

Explanation:

This line declares an array for 3 elements

string names[3];

This line prompts user for three names

cout<<"Please enter three names: "<<endl;

This following iteration lets user input the three names

for (int i = 0; i< 3;i++) { cin>>names[i]; }

The following iteration prints the three names in reverse order

for (int i = 2; i>= 0;i--) { cout<<names[i]<<endl; }

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Create a function printInfo(some_dict) that given a dictionary whose values are all lists, prints the name of each key along wit

aleksandrvk [35]

Answer:

def printInfo(some_dict):

print(len(some_dict['locations']), "LOCATIONS")

for location in some_dict['locations']:

print(location)

print()

print(len(some_dict['instructors']), "INSTRUCTORS")

for location in some_dict['instructors']:

print(location)

seattle = {

'locations': ['San Jose', 'Seattle', 'Dallas', 'Chicago', 'Tulsa', 'DC', 'Burbank'],

'instructors': ['Michael', 'Amy', 'Eduardo', 'Josh', 'Graham', 'Patrick', 'Minh', 'Devon']

}

printInfo(seattle)

Explanation:

7 0

2 years ago

burger hut is trying to decide if it can receive money from the government for providing employees with insurance .

lawyer [7]

Answer:

A cell grows to its full size, The cell copies its DNA

have a great weekends, hopefully it was the right answer!

8 0

2 years ago

Write a function: function solution(N); that, given a positive integer N, prints the consecutive numbers from 1 to N, each on a

koban [17]

Answer:

The program written in Python is as follows:

def solution(N):

concat = ""

for i in range(1,N+1):

if not(i%2 == 0 or i%3 ==0 or i%5 == 0):

print(str(i))

else:

if i%2 == 0:

concat= concat+"Codility"

if i%3 == 0:

concat= concat+"Testers"

if i%5 == 0:

concat= concat+"Coders"

print(concat)

concat = ""

N = int(input("Enter a positive integer: "))

solution(N)

Explanation:

This line declares the function

def solution(N):

This line initializes a variable named concat to an empty string

concat = ""

This line iterates from 1 to the input integer

for i in range(1,N+1):

This line checks if the current number of iteration is divisible by 2,3 or 5, if no, the number is printed

if not(i%2 == 0 or i%3 ==0 or i%5 == 0):

print(str(i))

If otherwise

else:

This lines checks if current number is divisible by 2; if yes the string "Codility" is concatenated to string concat

if i%2 == 0:

concat= concat+"Codility"

This lines checks if current number is divisible by 3; if yes the string "Testers" is concatenated to string concat

if i%3 == 0:

concat= concat+"Testers"

This lines checks if current number is divisible by 2; if yes the string "Coders" is concatenated to string concat

if i%5 == 0:

concat= concat+"Coders"

The concatenated string is printed using this line

print(concat)

This variable concat is intialized back to an empty string

concat = ""

The main method starts here

N = int(input("Enter a positive integer: "))

This line calls the defined function solution

solution(N)

6 0

2 years ago

Write a demo test to verify the above Rectangle object accessible from demo test main program and can execute display() method t

Sati [7]

Answer:

Explanation:

The Rectangle class was not provided in this question but after a quick online search I was able to find the class code. Due to this I was able to create a test code in the main Method of my program to create a Rectangle object and call it's display() method. The Test code and the output can be seen in the attached image below. While the code below is simply the Main Test Program as requested.

class Brainly {

public static void main(String[] args) {

Rectangle rectangle = new Rectangle(20, 8);

rectangle.display();

}

4 0

2 years ago

The return value is a one-dimensional array that contains two elements. These two elements indicate the rows and column indices

erma4kov [3.2K]

Answer:

In Java:

import java.util.Scanner;

import java.util.Arrays;

public class Main {

public static void main(String args[]) {

Scanner input = new Scanner(System.in);

int row, col;

System.out.print("Rows: "); row = input.nextInt();

System.out.print("Cols: "); col = input.nextInt();

int[][] Array2D = new int[row][col];

System.out.print("Enter array elements: ");

for(int i =0;i<row;i++){

for(int j =0;j<col;j++){

Array2D[i][j] = input.nextInt();

} }

int[] maxarray = findmax(Array2D,row,col);

System.out.println("Row: "+(maxarray[0]+1));

System.out.println("Column: "+(maxarray[1]+1));

}

public static int[] findmax(int[][] Array2D,int row, int col) {

int max = Array2D[0][0];

int []maxitem = new int [2];

for(int i =0;i<row;i++){

for(int j =0;j<col;j++){

if(Array2D[i][j] > max){

maxitem[0] = i;

maxitem[1] = j; } } }

return maxitem;

}

Explanation:

The next two lines import the scanner and array libraries

import java.util.Scanner;

import java.util.Arrays;

The class of the program

public class Main {

The main method begins here

public static void main(String args[]) {

The scanner function is called in the program

Scanner input = new Scanner(System.in);

This declares the array row and column

int row, col;

This next instructions prompt the user for rows and get the row input

System.out.print("Rows: "); row = input.nextInt();

This next instructions prompt the user for columns and get the column input

System.out.print("Cols: "); col = input.nextInt();

This declares the 2D array

int[][] Array2D = new int[row][col];

This prompts the user for array elements

System.out.print("Enter array elements: ");

The following iteration populates the 2D array

for(int i =0;i<row;i++){

for(int j =0;j<col;j++){

Array2D[i][j] = input.nextInt();

} }

This calls the findmax function. The returned array of the function is saved in maxarray

int[] maxarray = findmax(Array2D,row,col);

This prints the row position

System.out.println("Row: "+(maxarray[0]+1));

This prints the column position

System.out.println("Column: "+(maxarray[1]+1));

The main method ends here

}

The findmax function begins here

public static int[] findmax(int[][] Array2D,int row, int col) {

This initializes the maximum to the first element of the array

int max = Array2D[0][0];

This declares maxitem. The array gets the position of the maximum element

int []maxitem = new int [2];

The following iteration gets the position of the maximum element

for(int i =0;i<row;i++){

for(int j =0;j<col;j++){

if(Array2D[i][j] > max){

maxitem[0] = i; -- The row position is saved in index 0

maxitem[1] = j; -- The column position is saved in index 1} } }

This returns the 1 d array

return maxitem;

}

7 0

2 years ago