Answer:
Step-by-step explanation:
<u>Distance:</u>
<u>Speed:</u>
<u>Time:</u>
- t = d/s
- t = 7/8 : 3/8 = 7/8 * 8/3 = 7/3 = 2 1/3 min
Answer:
The interquartile range is the difference between the highest and lowest values in the middle of a data set.
Step-by-step explanation:
The range is the difference between the maximum and minimum value, hence, it cannot be greater than the maximum value, which is the greatest value in a dataset, the highest value a range could have being equal to the maximum value when the minimum vlaue of the dataset is equal to 0.
The mean is the average value of a dataset, hence, it cannot be greater than the maximum value.
The interquartile range is the middle 50% or half of a dataset and not the difference between the highest and lowest middle values in the middle. It is obtained by taking the difference of the upper and lower QUARTILE.
A
a and 143 are supplementary. So a + 143 = 180
a + 143 = 180 Subtract 143 from both sides.
a = 180 - 143
a = 37
B
b and 143 are vertically opposite angles and are equal
b = 143 degrees.
C
Interior angles on the same side of a transversal for parallel lines are supplementary
b + c = 180
143 + c = 180
c = 37
D
c + d + 85 = 180 degrees
37 + d + 85 = 180
d + 122 = 180
d = 180 - 122
d = 58
E
e = c They are vertically opposite.
e =37
F
All triangles have 180 degrees.
e + f + 90 = 180 degrees.
37 + f + 90 = 180
f + 127 = 180
f = 180 - 127
f = 53
G
G and 48 are opposite 2 equal sides. So G and 48 are equal
G = 48
H
h + 48 + 48 = 180
h + 96 = 180
h = 84
K
K and H are supplementary
K + H = 180
k + 84 = 180
k = 95
M
m+ k + d = 180
M + 95 + 58 = 180
M + 143 = 180
M = 37
P
the top angle is 2*m and 2m is bisected. You are using the m on the left.
P + 85 + M = 180
P + 85 + 37 = 180
P + 122 = 180
p = 180 - 122
p = 58
R
r + p are supplementary.
r + p = 180
r + 58 = 180
r = 180 - 58
r = 122
S
s + r + c + b = 360 All quadrilaterals have 360 degrees.
s + 122 + 37 + 143 = 360
s + 302= 360
s = 360 - 302
s = 58
Answer:
one solution
(second option listed)
Step-by-step explanation:
We can that these two lines, each representing one equation/function, only meet at one specific value.
In a system of equations, we are essentially looking for a solution that works for both equations.
So, if both lines share a point/value (meaning they intersect), that point is a solution to the system of equations.
Because these lines only overlap at one point, this system of equations has one solution.
Answer:
a) The mean number of cases is 0.14608 cases.
b) The probability that the number of cases is exactly 0 or 1 is 0.990.
c) The probability of more than one case is 0.010
d) No, because the probability of more than one case is very small
Step-by-step explanation:
We can model this problem with a Poisson distribution, with parameter:

a) The mean amount of cases is equal to the parameter λ=0.14608.
b) The probability of having 0 or 1 cases is:

c) The probability of more than one case is:

d) The cluster of 4 cases can not be due to pure chance, as it is a very high proportion of cases according to the average rate. Just having more than one case has a probability of 1%.