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DanielleElmas [232]
3 years ago
5

Please help with these too (10-15)

Mathematics
2 answers:
kakasveta [241]3 years ago
4 0
10. 64in > 5ft
11. 2 mi < 3,333yds
12. 36yd 2 ft< 114 ft 2 in
13. They are =
14. 4ft 7in < 56 in
15. 25 ft > 8yd 11 in
viktelen [127]3 years ago
3 0
#10 is > sorry I do not knowthe rest.
You might be interested in
Wich measure is less than 435 inches
podryga [215]
435 inches = 36 1/4 ft.

So, the answer would be D) 12 ft. 3 in. hope this helps
3 0
3 years ago
Help me i think its add 24 to both sides
umka2103 [35]

It is given in the question that

Steven is solving the equation

3(8-2x)+40=34

He begins with the following two steps.

Step 1: 3(8)+3(-2x)+40=34  Step 2: 24-6x+40=34

And we have to find , what will be the next step in solving the equation.

First we combine the like terms. And the like terms are 24 and 40. So we have to add 24 and 40. And that will be the next step.

So the correct option is the last option.

8 0
3 years ago
So L x W=A so I have a problem where one side is 9cm on the other sides there's nothing​
Eduardwww [97]

Answer:

The other sides equal 9cm also because a square has four equal sides.

L=9cm * W=9cm =A

A=81 cm

7 0
2 years ago
CAN SOMEBODY PLEASE HELP ME NOW I AM IN A RUSH!!!!!!!!!!!!!!!!!!!
cupoosta [38]

Answer:

i’m pretty sure it is 3 but i could be wrong

Step-by-step explanation:

3 0
3 years ago
<img src="https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B5x%2F8y%7D" id="TexFormula1" title="\sqrt[4]{5x/8y}" alt="\sqrt[4]{5x/8y}" al
Furkat [3]

Answer:  \frac{\sqrt[4]{10xy^3}}{2y}

where y is positive.

The 2y in the denominator is not inside the fourth root

==================================================

Work Shown:

\sqrt[4]{\frac{5x}{8y}}\\\\\\\sqrt[4]{\frac{5x*2y^3}{8y*2y^3}}\ \ \text{.... multiply top and bottom by } 2y^3\\\\\\\sqrt[4]{\frac{10xy^3}{16y^4}}\\\\\\\frac{\sqrt[4]{10xy^3}}{\sqrt[4]{16y^4}} \ \ \text{ ... break up the fourth root}\\\\\\\frac{\sqrt[4]{10xy^3}}{\sqrt[4]{(2y)^4}} \ \ \text{ ... rewrite } 16y^4 \text{ as } (2y)^4\\\\\\\frac{\sqrt[4]{10xy^3}}{2y} \ \ \text{... where y is positive}\\\\\\

The idea is to get something of the form a^4 in the denominator. In this case, a = 2y

To be able to reach the 16y^4, your teacher gave the hint to multiply top and bottom by 2y^3

For more examples, search out "rationalizing the denominator".

Keep in mind that \sqrt[4]{(2y)^4} = 2y only works if y isn't negative.

If y could be negative, then we'd have to say \sqrt[4]{(2y)^4} = |2y|. The absolute value bars ensure the result is never negative.

Furthermore, to avoid dividing by zero, we can't have y = 0. So all of this works as long as y > 0.

3 0
2 years ago
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