All categories

3 years ago

Determine whether the given point (-6,2) is a solution of the equation y = -2x - 1

2 answers:

6 0

Its just a matter of subbing to see if it is true

y = -2x - 1
(-6,2)...x = -6 and y = 2
sub
2 = -2(-6) - 1
2 = 12 - 1
2 = 11....nope....it is not a solution

Basile [38]3 years ago

3 0

Y-y1= m(x-x1)

y-2= -2(x+6)

y-2= -2x-12

y= -2x-10
Unless there is supposed to be a zero at the end of that 1, then the answer is no

You might be interested in

MARSVECTORCALC6 3.4.020. My Notes A rectangular box with no top is to have a surface area of 64 m2. Find the dimensions (in m) t

ioda

Answer:

We would have

$l =w =\frac{8\sqrt{3}}{3} \\h = \frac{8\sqrt{3}}{6}$

where " l " is length, " w" is width and "h" is height.

Step-by-step explanation:

Step 1

Remember that

Surface area for a box with no top = $lw+2lh+2wh = 64$

where " l " is length, " w" is width and "h" is height.

Step 2.

Remember as well that

Volume of the box = $l*w*h$

Step 3

We can now use lagrange multipliers. Lets say,

$F(l,w,h) = lwh$

and

$g(l,w,h) = lw+2lh+2wh = 64$

By the lagrange multipliers method we know that

$\nabla F = \lambda \nabla g$

Step 4

Remember that

$\nabla F = (wh,lh,lw)$

and

$\nabla g = (w+2h,l+2h , 2w+2l)$

So basically you will have the system of equations

$wh = \lambda (w+2h)\\lh = \lambda (l+2h)\\lw = \lambda (2w+2l)$

Now, remember that you can multiply the first eqation, by "l" the second equation by "w" and the third one by "h" and you would get

$lwh = l\lambda (w+2h)\\\\lwh = w\lambda (l+2h)\\\\lwh = h\lambda (2w+2l)$

Then you would get

$l\lambda (w+2h) = w\lambda (l+2h) = h\lambda (2w+2l)$

You can get rid of $\lambda$ from these equations and you would get

$lw+2lh = lw+2wh = 2wh+2lh$

And from those equations you would get

$l = w =2h$

Now remember the original equation

$lw+2lh+2wh = 64$

If we plug in what we just got, we would have

$l^{2} + l^{2} + l^2 = 64 \\3l^{2} = 64 \\l = w = \frac{8\sqrt{3} }{3} \\h = \frac{8\sqrt{3} }{6}$

7 0

4 years ago

ΔDOG has coordinates D (3, 2), O (2, −4) and G (−1, −1). A translation maps point D to D' (2, 4). Find the coordinates of O' and

geniusboy [140]

Answer:

see explanation

Step-by-step explanation:

Given D(3, 2 ) → D'(2, 4 )

The x- coordinate of D' is 1 less than D and the y- coordinate of D' is 2 more than D, thus the translation rule is

(x, y ) → (x - 1, y + 2 )

Apply this rule to points O and G

O( 2, - 4 ) → O'(2 - 1, - 4 + 2 ) → O'(1, - 2 )

G(- 1, - 1 ) → G'(- 1 - 1, - 1 + 2 ) → G'(- 2, 1 )

6 0

4 years ago

A=20 cm<br> b=48 cm<br> What is the length of c?

Ainat [17]

The value of c is 52

8 0

3 years ago

What is the monthly payment on a 15-year loan of $72,700 if the annual interest rate is 12%?

Marianna [84]

Answer:

872.52

Step-by-step explanation:

3 0

3 years ago

Need help finding x when Circle G and Circle U are similar.

svet-max [94.6K]

I think it would be 15

5 0

3 years ago