Answer:
The order of the differential equation to be formed is equal to the number of arbitrary constants present in the equation of the family of curves.
Consider the equation f ( x, y ,c1 ) = 0 -------(1) where c1 is the arbitrary constant. We form the differential equation from this equation. For this, differentiate equation (1) with respect to the independent variable occur in the equation.
Eliminate the arbitrary constant c from (1) and its derivative. Then we get the required differential equation.
Suppose we have f ( x, y ,c1 ,c2 ) = 0 . Here we have two arbitrary constants c1 and c2 . So, find the first two successive derivatives. Eliminate c1 and c2 from the given function and the successive derivatives. We get the required differential equation.
Note
The order of the differential equation to be formed is equal to the number of arbitrary constants present in the equation of the family of curves.
Answer:
y=-2/5x+8
Step-by-step explanation:
Step 1: Begin by changing the equation into slope-intercept form. Subtract 2x to both sides to get 5y=-10-2x. Divide 5 to both sides to isolate the variable, y. You should get y=-2/5x-2.
Step 2: Because we are looking for a line parallel to the given line, the slope should be the same, but the y-intercept should be different. Remove -2 to replace it with b, so it's unknown. The equation should be y=-2/5x+b. Plug in the ordered pair, (10, 4), into the equation to get 4=-2/5(10)+b. Multiply -2/5 and 10 to get -4. Add -4 to both sides and b=8. Plug in 8 and your final equation should be y=-2/5x+8.
Answer: 2x√5
Step-by-step explanation:
It would be 100 tens your welcome.
<span>y = 3x - 4
</span><span>(4,2); when x = 4; y = 3(4) - 4 = 9 ........FALSE
(1, -1)</span>; when x = 1; y = 3(1) - 4 = -1 ........TRUE<span>
(-1, -7)</span>; when x = -1; y = 3(-1) - 4 = -7 ........TRUE<span>
(2, 2)</span>; when x = 2; y = 3(2) - 4 = 2 ........TRUE
answer
(1, -1)
(-1, -7)
(2, 2)
