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Lisa [10]
3 years ago
13

What is the distance between corresponding points of adjacent waves

Physics
2 answers:
expeople1 [14]3 years ago
8 0

Answer:

Wavelength

Explanation:

The distance between corresponding points of adjacent waves is known as the wavelength.

In a wave motion, the point at which displacement is at maximum is known as the crest of the wave while the point where the displacement is at minimum is known as the trough of the the wave.

The distance between these two successive crest and trough of he wave as known as its wavelength.

Wavelength can be expressed as a function of frequency and velocity of a wave.

alina1380 [7]3 years ago
3 0

Answer:

Wavelength

Explanation:

Wave properties are elements we can measure for ANY wave. These properties are: amplitude, wavelength, frequency, period, and velocity.

Wavelength is one way of measuring the size of waves. It is the distance between two corresponding points on adjacent waves, usually measured in meters. The wavelength of a transverse wave can be measured as the distance between two adjacent crests

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GalinKa [24]
Answer is A.) 40 m/km

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Mike lives in the northern United States minnesota and nick lives in the southern United States Louisiana. When they both feel i
Viktor [21]

Complete question is;

Mike lives in the northern United States (in Minnesota) and Nick lives in the southern United States (Louisiana). When they both feel insulted by the same individual, Nick will be more likely to have a(n) ________ cortisol response and show ________ levels of physical aggression.

Answer:

- A hyper cortisol response

- higher levels of physical aggression

Explanation:

In study of hormones in the human body, it has been discovered that cortisol is a stress inducing hormone. Now, if they are in the summer when it is hot, it has been proven that's when the cortisol hormone circulates in a very large manner in the blood. This leads to frustration and as well possibly physical aggression.

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3 years ago
When an unbalanced force acts on an object the change in the objects ____or ____ depends on the size and direction of the force
timama [110]

When an unbalanced force acts on an object the change in the object state of rest or motion depends on the size and direction of the force.

If a body is at state of rest or motion, when an unbalanced external force acts on it, its starts moving in the direction of force and magnitude of its velocity or acceleration depends on the magnitude of force applied.

7 0
3 years ago
Read 2 more answers
A 50.3-kg person, running horizontally with a velocity of 2.44 m/s, jumps onto a 13.4-kg sled that is initially at rest. (a) Ign
Simora [160]

Answer:

a

  v =  1.9267 \  m/s

b

The value is    \mu = 0.0063        

Explanation:

From the question we are told that

      The  mass of the person is  m_1  =  50.3 \  kg

       The  horizontal velocity is  u_1  =  2.44 \  m/s

       The mass of the shed is  m_2  =  13.4 \  kg

        The distance covered is  d =  30 \ m

Generally from the law of momentum conservation we have that

        m_1 *  u_1 + m_2 * u_2 =  (m_1 + m_2)v

Here  u_2 is the initial velocity of the shed which is  0 m/s  

       50.3 *  2.44 + 13.4  * 0 =  (50.3 + 13.4) v

=>    v =  1.9267 \  m/s

Generally the workdone by friction is mathematically represented as  

          W = \Delta  KE          

          W =  \frac{1}{2}  *   m  *  (v_f  -  v  )

Here v_f is the final velocity of the person and the shed when they come to rest and the value is  v_f = 0 \ m/s

 Generally this workdone  by friction is also mathematically represented as

           W = - \mu *  m *  g * d

=>        - \mu *  m *  g * d =  \frac{1}{2}  *   m  *  (v_f  -  v  )

=>       \mu =  - \frac{0.5 *  ( v_f^2 - v^2 )}{g * d }

=>         \mu =-  \frac{0.5 *  ( 0^2 -  1.9267^2 )}{9.8 *  30 }

=>         \mu = 0.0063        

6 0
3 years ago
When a falling object reaches a speed called terminal velocity, its speed no longer increases. the object is losing gravitationa
Ronch [10]
As far as I know, the energy just winds up as heat dispersing into the atmosphere or heating up the falling object.
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3 years ago
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