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3 years ago

What is the distance between corresponding points of adjacent waves

Physics

2 answers:

expeople1 [14]3 years ago

8 0

Answer:

Wavelength

Explanation:

The distance between corresponding points of adjacent waves is known as the wavelength.

In a wave motion, the point at which displacement is at maximum is known as the crest of the wave while the point where the displacement is at minimum is known as the trough of the the wave.

The distance between these two successive crest and trough of he wave as known as its wavelength.

Wavelength can be expressed as a function of frequency and velocity of a wave.

alina1380 [7]3 years ago

3 0

Answer:

Wavelength

Explanation:

Wave properties are elements we can measure for ANY wave. These properties are: amplitude, wavelength, frequency, period, and velocity.

Wavelength is one way of measuring the size of waves. It is the distance between two corresponding points on adjacent waves, usually measured in meters. The wavelength of a transverse wave can be measured as the distance between two adjacent crests

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An ideal gas initially at 4.00atm and 350 K is permitted

Nuetrik [128]

Explanation:

It is given that initially pressure of ideal gas is 4.00 atm and its temperature is 350 K. Let us assume that the final pressure is $P_{2}$ and final temperature is $T_{2}$ .

(a) We know that for a monoatomic gas, value of $\gamma$ is \frac{5}{3}[/tex].

And, in case of adiabatic process,

$PV^{\gamma}$ = constant

also, PV = nRT

So, here $T_{1}$ = 350 K, $V_{1} = V$ , and $V_{2} = 1.5 V$

Hence, $\frac{T_{2}}{T_{1}} = (\frac{V_{1}}{V_{2}})^{\gamma -1}$

$\frac{T_{2}}{350 K} = (\frac{V}{1.5V})^{\frac{5}{3} -1}$

$T_{2}$ = 267 K

Also, $P_{1}$ = 4.0 atm, $V_{1} = V$ , and $V_{2} = 1.5 V$

$\frac{P_{2}}{P_{1}} = (\frac{V_{1}}{V_{2}})^{\gamma}$

$\frac{P_{2}}{4.0 atm} = (\frac{V}{1.5V})^{\frac{5}{3}}$

$P_{2}$ = 2.04 atm

Hence, for monoatomic gas final pressure is 2.04 atm and final temperature is 267 K.

(b) For diatomic gas, value of $\gamma$ is \frac{7}{5}[/tex].

As, $PV^{\gamma}$ = constant

also, PV = nRT

$T_{1}$ = 350 K, $V_{1} = V$ , and $V_{2} = 1.5 V$

$\frac{T_{2}}{T_{1}} = (\frac{V_{1}}{V_{2}})^{\gamma -1}$

$\frac{T_{2}}{350 K} = (\frac{V}{1.5V})^{\frac{7}{5} -1}$

$T_{2}$ = 289 K

And, $P_{1}$ = 4.0 atm, $V_{1} = V$ , and $V_{2} = 1.5 V$

$\frac{P_{2}}{P_{1}} = (\frac{V_{1}}{V_{2}})^{\gamma}$

$\frac{P_{2}}{4.0 atm} = (\frac{V}{1.5V})^{\frac{7}{5}}$

$P_{2}$ = 2.27 atm

Hence, for diatomic gas final pressure is 2.27 atm and final temperature is 289 K.

6 0

4 years ago

For a certain ideal Carnot engine, the hot reservoir is 35°C higher than the cold reservoir. If this engine is to have an effici

lord [1]

Answer:

Temperature of the hot reservoir is 1540K

Explanation:

$E= 1- \frac{T_{c}}[tex]{T_h}=308+{T_c}\\Efficiency of a carnot engine is given by the aboveTc=temperature of the cold reservoirTh= temperature of the hot reservoirK=273+ 35 (convert 35°C to kelvin)K=308k{T_h}={T_c}+308-----------------------(equation 1)20%=1-{T_c}/{T_h}$

0.2=({T_c}+308-{T_c})/{T_c}+308

.2({T_c}+61.6=308

0.2{T_c}=246.4

{T_c}=1232

recall from equation 1

{T_h}=308+1232

{T_h}=1540K

5 0

3 years ago

Explain what happens to the sound waves when a singer hits the high pitched notes during the National Anthem. Be sure to use the

Tasya [4]

Answer: The frequency increases as the pitch increases, and the amplitude increases as the volume increases

Explanation:

Waves have the property of:

v = f*λ

where v is the speed of the wave (which is almost constant for soundwaves, v = 340 m/s)

f is the frequency of the wave, and λ is the wavelength.

Now, we know that when the pitch of a note increases, also does the frequency of the soundwave (so the wave oscillates faster).

Now, we also want to include the amplitude of the soundwave in this.

The amplitude is related to the volume of the soundwave (actually is related to the energy, and as higher is the energy, more "loud" is the sound).

As the high pitch part is usually "louder", we can assume that we have an amplitude increase.

Then the answer would be:

"The frequency increases as the pitch increases, and the amplitude increases as the volume increases"

4 0

3 years ago

100 newtons 5 seconds how do you find the momentum

UNO [17]

F = ma = m dv/dt

F dt = m dv

integrate both sides ( assuming constant force , mass) , zero inital conditions

Ft = mv

mv = P

P = Ft = 5 * 100 = 500 N.s

3 0

3 years ago

PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!

cluponka [151]

I would say Anthony has more power than Angel. If they are both exerting the same force on the box, which isnt really mentioned here, which is why I believe this is a bit vague, then the both do the same work. So, if the work is equal then the person with the lower time period would have more power. Since Anthony only took 38 seconds, compared to Angel's 42 I would say that Anthony has more power than Angel.

6 0

3 years ago

Read 2 more answers