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3 years ago

PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!

Physics

2 answers:

Makovka662 [10]3 years ago

8 0

Question 1

In order to do work, the force vector must be

in the same direction as the displacement vector and the motion.

Question 2

In which of the following cases is work being done on an object?

Pulling a trailer up a hill

Question 3

Which situation is an example of NOT doing work?

carrying a box

Question 4

Work is measured in

Joules

Question 5

To find the work done, the force exerted and distance moved are multiplied. A couch is moved twice before you are happy with its placement. The same force was used to move the couch both times. If more work is done the first time it is moved, what do you know about the distance it was moved?

When more work was done, the couch was moved further.

Question 6

A weight lifter raises a 1600 N barbell to a height of 2.0 meters. How much work was done? W = Fd

3200 Joules

Question 7

You and a friend (Alex) are at a a tree-top adventure park .. . . part of the course requires you to climb up a rope. You both climb the same rope in the same amount of time. However, the tension in the rope is greater

when Alex climbs. Who did the most work?

Alex did - more tension means more force - more force means more work was done

Question 8

Doing work at a faster rate creates power.

more

Question 9

In one challenge on the Titan Games, competitors have to lift 200 pounds up a long ramp. Angel is able to move the weight in 42 seconds. Anthony gets it done in only 38 seconds. Which statement is true?

Anthony has more power than Angel.

Question 10

A mountain climber exerts 41,000 J of work to climb a cliff. How much power does the climber need if she wants to finish in only 500 seconds? Power = Work / time

82 Watts

Question 11

Your family is moving to a new apartment. While lifting a box 83 Joules of work is done to put the box on a truck, you exert an upward force of 75 N for 3 s. How much power is required to do this? (Hint: You only need two of the 3 numbers given!) Power = Work / time

27.7 Watts

<em>*100% CORRECT ANSWERS</em>

cluponka [151]3 years ago

6 0

I would say Anthony has more power than Angel. If they are both exerting the same force on the box, which isnt really mentioned here, which is why I believe this is a bit vague, then the both do the same work. So, if the work is equal then the person with the lower time period would have more power. Since Anthony only took 38 seconds, compared to Angel's 42 I would say that Anthony has more power than Angel.

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the passengers in a roller coaster feel 50 heavier than their true weight as the car goes through a dip with a 30m radius of cur

NeTakaya

Answer:

v = 12.12 m/s

Explanation:

Given that,

Radius of the curvature, r = 30 m

To find,

The car's speed at the bottom of the dip.

Solution,

Let mg is the true weight of the passenger. When it is moving in the circular path, the centripetal force act on it. It is given by :

$F=\dfrac{mv^2}{r}$

The normal reaction of the passenger is given by :

$N=mg-50\%mg$

N = 1.5 mg

Let v is the car's speed at the bottom of the dip. It can be calculated as:

$1.5\ mg-mg=\dfrac{mv^2}{r}$

$v=\sqrt{0.5gr}$

$v=\sqrt{0.5\times 9.8\times 30}$

v = 12.12 m/s

So, the speed of the car at the bottom of the dip is 12.12 m/s. Hence, this is the required solution.

7 0

3 years ago

A car runs 4200m on a straight path in 40 minute. find its velocity?

Akimi4 [234]

Answer:

velocity = displacement/time

= 4200m/ 2400s

= 1.75 m/s

Explanation:

40 minutes × 60 = 2400 seconds

8 0

3 years ago

Which is this the correct variable for the equation "____= displacement divided by time"?

zheka24 [161]

The answer is velocity

3 0

3 years ago

A mine car, whose mass is 440kg, rolls at a speed of 0.50m/s on ahorizontal track, as the drawing shows. A 150kg chunk of coalha

ella [17]

Answer: 0.56 m/s

Explanation:

hello, there is 25° inclination angle for the chute in the drawing. Thankfully, I know this problem. The conservation of momentum.

so there are X and Y components for the momentum in this problem. The Y component is not conserved as when the coal gets in the cart, the normal force exerted by the surface reduces it to 0.

Now, the X component is definitely conserved here.

so you have the momentum of the cart which is 440*0.5 added to the momentum of the chunk which is 150*0.8*cos(25°), that is the momentum before the coupling between the objects. Afterwards both objects will have the same velocity, so we write the equation like this:

$440*0.5 + 150*0.8*cos(25) = 440*v_{final} + 150*v_{final} \\ => 220+120*cos(25) = (440+150)v_{final} => v_{final} = \frac{220+120*cos(25)}{590} = 0.56 m/s$

3 0

3 years ago

A balloon tied up with a wooden piece is moving upward with velocity of 15m/s. At a height of 300m above the ground, the wooden

Inessa05 [86]

Assume the wooden piece prevents the balloon from rising, is not so heavy as to cause the balloon to descend. and the 15 m/s is horizontal velocity “riding the wind,” That horizontal velocity does not affect the time the wood will take to reach the ground after release. Initial vertical velocity is zero.

s = u t + 1/2 g t^2

s is the height above ground, 300 m.

u is initial vertical velocity, zero.

t is time to reach the ground.

g is acceleration of gravity near Earth, 9.8 m/s^2.

300 m = 0 t + 1/2 (9.8 m/s^2) t^2

300 m = (4.9 m/s^2) t^2

61.22 s^2 = t^2

7.82 seconds = t

6 0

3 years ago