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hjlf
3 years ago
11

100 newtons 5 seconds how do you find the momentum

Physics
1 answer:
UNO [17]3 years ago
3 0
 F = ma = m dv/dt

F dt = m dv

integrate both sides ( assuming constant force , mass) , zero inital conditions

Ft = mv

mv = P

P = Ft = 5 * 100 = 500 N.s 

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What is the
Len [333]

Answer:

d=5\ g/cm^3

Explanation:

Given that,

Mass of the object, m = 100 grams

Volume of the object, V = 20 cm³

We need to find the density of the object. We know that, density is equal to mass per unit volume. So,

d=\dfrac{m}{V}\\\\d=\dfrac{100\ g}{20\ cm^3}\\\\d=5\ g/cm^3

So, the density of the object is equal to 5\ g/cm^3.

6 0
3 years ago
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Bas_tet [7]

Answer:

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Explanation:

8 0
3 years ago
Match these items.
aleksandrvk [35]

Answer:

Here's your answer :

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3 0
3 years ago
10. At point A, a runner is jogging 5 m/s. Forty seconds later, at point B
kondaur [170]

Answer:

Deceleration of 0.075m/s²

Explanation:

Given parameters:

Initial velocity  = 5m/s

Time  = 40s

Final velocity  = 2m/s

Unknown:

The jogger's acceleration  = ?

Solution:

To solve this problem, we use;

         a  = \frac{v - u}{t}  

a is the acceleration

v is the final velocity

u is the initial velocity

t is the time taken

      a  = \frac{2 - 5}{40}   = - 0.075m/s²

5 0
3 years ago
Two masses, each weighing 1.0 × 103 kilograms and moving with the same speed of 12.5 meters/second, are approaching each other.
pav-90 [236]

Answer:

A. 1.6 × 105 joules

Explanation:

As per the question, the data given in the question is as follows

Number of masses = 2

Each weightage = 1.0 \times 2.3

Speed = 12.5 meters/ second

Based on the above information, the approximate kinetic energy after the collision is

A perfectly elastic collision is described as one where the collision does not cause any loss of kinetic energy. 

So we sum the kinetic energy of each kind of system which is given below:

Kinetic energy is

= 0.5(1.0 \times 10^3) (12.5)^2 + 0.5 (1.0 \times 10^3) (12.5 )^2

= 156250 J

= 1.6 \times 10^5 J

8 0
4 years ago
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